python - 定位列表中重复项的位置及其位置

Question

我想调用列表中的某些词(长度超过 11 个字符)，并找出可以通过在手机上使用相同的按键输入的词，例如“compurgations”和“constrictions”都共享相同的代码(2667874284667)。

我能够通过笨拙但有效的编码将每个单词变成一个数字字符串。

numbers = []
dial = []
for word in lowers:
    if len(word)>11 and "\'" not in word:
        dial.append(word)
    if len(word)>11 and "\'" not in word:
            worda = word.replace('a','2')
            wordb = worda.replace('b','2')
            wordc = wordb.replace('c','2')
            wordd = wordc.replace('d','3')
            worde = wordd.replace('e','3')
            wordf = worde.replace('f','3')
            wordg = wordf.replace('g','4')
            wordh = wordg.replace('h','4')
            wordi = wordh.replace('i','4')
            wordj = wordi.replace('j','5')
            wordk = wordj.replace('k','5')
            wordl = wordk.replace('l','5')
            wordm = wordl.replace('m','6')
            wordn = wordm.replace('n','6')
            wordo = wordn.replace('o','6')
            wordp = wordo.replace('p','7')
            wordq = wordp.replace('q','7')
            wordr = wordq.replace('r','7')
            words = wordr.replace('s','7')
            wordt = words.replace('t','8')
            wordu = wordt.replace('u','8')
            wordv = wordu.replace('v','8')
            wordw = wordv.replace('w','9')
            wordx = wordw.replace('x','9')
            wordy = wordx.replace('y','9')
            wordz = wordy.replace('z','9')
            numbers.append(wordz)

numberset = set(numbers)   

然后我打算搜索以查看每个数字出现了多少次，如果大于 1，则记录位置并将其从另一个列表中拉到一起，将它们作为元组提供。我不知道如何找出哪些号码与位置共享相同的号码。

Answer 1

建立字典可能是个好主意

charmap = { 'a' : '2', 'b' : '2', etc... }
wordz = defaultdict(list)
for word in lowers:
    wordz[''.join(charmap[c] for c in word)].append(word)

for k,v in wordz.items():
    if len(v) > 1:
        print('{}:{}'.format(k, v))

会给你:

2667874284667:['compurgations', 'constrictions']
...