python - 调用另一个 python 脚本的 main() 并获取 STDOUT 结果

Question

我正在尝试使用子进程调用另一个本地脚本。

本地脚本将结果打印到屏幕上。

本地:

def main():
    """
        main function
        controls the method call, the method is decided by TS runner
    """

    sParams = ScriptParamHandler()
    paramsList = ['TestName']  # ordered list of parameters
    paramsDict = sParams.AnalyzeParametersForScript(paramsList)

    mainReturn = None

    with ProductXXXXX() as testSequence:

        testSequence.testFixture.InitDevices()

        func = getattr(testSequence, paramsDict['TestName'])

        returnVal = func()

        print paramsDict['TestName'], "\n", returnVal, "\n"

if __name__ == "__main__":
    main()

调用脚本:

with BasicRunner(testSet, testSetLocation, paramsDict['ProfileName']) as testRunner:

    if testRunner.CheckFolderAndFile():

        testRunner.GetProfile()

        for test in testRunner.testList:

            testRunner.logger.Info("Test {} started...".format(test))

            testResult = subprocess.call(testRunner.tsPyFile + " " + test, shell=True)

            testRunner.logger.Info("Test {} result {}".format(test, testResult))

    else:

        pass

我希望调用者脚本 testResult 成为本地脚本的 stout。

我试过 stdout=subprocess.PIPE 和 subprocess.check_output() 但没有成功，也许有人可以给我一些更好的方向？

Answer 1

通过@shshank评论解决，这是解决方案:

proc = subprocess.Popen(['python', testRunner.tsPyFile, test], stdout=subprocess.PIPE, stderr=subprocess.STDOUT)
stdoutValue = proc.communicate()[0]