python - 如何在事件回调之间保持 python 生成器的状态

Question

所以我正在尝试学习 leap-motion SDK并在 4-5 年没有接触 python 之后重新学习它，我在 python 2.7 中遇到了生成器问题

基本上我有一个单词列表，每次跳跃 Action 选择一个新的“圆圈”手势时，我都想打印列表中的下一个单词。我所看到的是，每次 on_frame 回调触发时，只会打印列表中的第一个单词。我相信正在发生的事情是 python 运行时忘记了事件之间生成器的状态。有什么方法可以在手势事件之间保持生成器状态？

if not frame.hands.is_empty:
        for gesture in frame.gestures():
            if gesture.type == Leap.Gesture.TYPE_CIRCLE:
                circle = CircleGesture(gesture)
                # Determine clock direction using the angle between the pointable and the circle normal
                action = None
                if circle.pointable.direction.angle_to(circle.normal) <= Leap.PI/4:
                    action = GestureActions.clockwiseCircleGesture()
                else:
                    action = GestureActions.counterClockwiseCircleGesture()

                print action.next()

  def clockwiseCircleGesture():
       words = ["You", "spin", "me", "right", "round", "baby", "right", "round", "like", "a", "record", "baby",                          "Right", "round", "round", "round", "You", "spin", "me", "right", "round", "baby", "Right", "round", "like", "a",
         "record", "baby", "Right", "round", "round", "round"]
      for word in words:
          yield word

任何对此的见解都会很棒。谢谢

Answer 1

我怀疑每次触发事件时您的action 变量都会被重置。

在事件处理函数之外初始化生成器。看起来您可能需要两个，clockwise_action 和 counterclockwise_action。