python - 函数内的变量

Question

您好，我是编程新手，请多多包涵。我正在尝试编写一个程序，要求您从三种选择中选择一种颜色，然后生成自己的随机颜色，并根据您的颜色是否与生成的颜色相匹配来告诉您输赢。我似乎无法确定我的语法，而且我不断收到我不熟悉的错误。这是我的程序。

import random


def ranred():
    global color
    color = 1
    global color_out
    color_out = "purple"
    f_color(color, color_in, color_out)
    return color, colorq


def ranblack():
    global color
    color = 2
    global color_out
    color_out = "black"
    f_color(color, color_in, color_out)


def ranpurple():
    global color
    color = 3
    global color_out
    color_out = "purple"
    f_color(color, color_in, color_out)


def f_color(color, color_in, color_out):
    print (color_out)
    if color == color_in:
        print ("win")
    else:
        print ("lose")


def main():
    color_in = input("Purple, Black or Red? ")
    Purple = 1
    purple = 1
    Black = 2
    black = 2
    Red = 3
    red = 3
    randomcolor1 = random.randrange(0, 2)
    randomcolor2 = random.randrange(0, 2)
    if randomcolor1 == 1 and randomcolor2 == 1:
        ranred()
    if randomcolor1 == 2 and randomcolor2 == 2:
        ranblack()
    if randomcolor1 == 2 and randomcolor2 == 1:
        ranpurple()
    if randomcolor1 == 1 and randomcolor2 == 2:
        ranpurple()

main()

Answer 1

您所解释的错误:

def f_color(color,color,color_out):

接受两个参数color。您只能有一个名为 color 的参数:

def f_color(color, color_out):