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java - 将数据从 XML 返回到 UI

转载 作者:太空宇宙 更新时间:2023-11-04 10:38:22 25 4
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我有一些代码循环遍历 XML 文件,并获取 <savedPositions> 的每个实例。 。我正在尝试将每个数据添加到一个数组中,以便我可以返回它并在 UI 中使用字符串 - 我不确定如何通过显示 <savedPositions> 的每个实例将数据读回到我的应用程序中单击每个按钮。这意味着我只得到 <savedPositions> 的一个实例显示到我的文本框中。

我该如何做到这一点,以便在每个按钮上单击时,文本框都会更新为下一个 <savedPositions>信息? - 谢谢

我的 XML:

<savedPositions>
<savedPosition>
<nBehaviour>nBehaviour1</nBehaviour>
<aBehaviour>aBehaviour1</aBehaviour>
<findings>findings1</findings>
<forces>forces1</forces>
<gap>gap1</gap>
<position1>0.6488889</position1>
<position2>-1000.0</position2>
</savedPosition>
<savedPosition>
<nBehaviour>nBehaviour2</nBehaviour>
<aBehaviour>aBehaviour2</aBehaviour>
<findings>findings2</findings>
<forces>aBehaviour2</forces>
<gap>gap2</gap>
<position1>-1000.0</position1>
<position2>-1000.0</position2>
</savedPosition>
</savedPositions>

读取 XML 代码:

public class XmlToObject {

public static ArrayList<ArrayList<String>> main() {

ArrayList<ArrayList<String>> obj1 = new ArrayList<ArrayList<String>>();
ArrayList<ArrayList<String>> obj = new ArrayList<ArrayList<String>>();

try {
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document d = db.parse("/home/nicolas/savedPos.xml");
XPath xp = XPathFactory.newInstance().newXPath();
NodeList nl = (NodeList) xp.compile("//savedPosition").evaluate(d, XPathConstants.NODESET);
System.out.println("number of saved positions " + nl.getLength());

for (int i = 0; i < nl.getLength(); i++) {

String a = (xp.compile("./nBehaviour").evaluate(nl.item(i)));
String b = (xp.compile("./aBehaviour").evaluate(nl.item(i)));
String c = (xp.compile("./gap").evaluate(nl.item(i)));
String d1 = (xp.compile("./forces").evaluate(nl.item(i)));
String e = (xp.compile("./findings").evaluate(nl.item(i)));
String f = (xp.compile("./position1").evaluate(nl.item(i)));
String g = (xp.compile("./position2").evaluate(nl.item(i)));

ArrayList<String> savedPosition = new ArrayList<String>();
savedPosition.add(a);
savedPosition.add(b);
savedPosition.add(c);
savedPosition.add(d1);
savedPosition.add(e);
savedPosition.add(f);
savedPosition.add(g);

obj.add(savedPosition);

}

return obj;

} catch (Exception l) {
System.out.println(l.getMessage());
}

return obj1;
}
}

单击按钮时调用 XML:

load.addActionListener(new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {

ArrayList<ArrayList<String>> obj = XmlToObject.main();

for(ArrayList<String> r: obj){
for(int i = 0; i < r.size(); i++){
System.out.println(r.get(i) + "");
}
textArea.setText(r.get(0));
textArea1.setText(r.get(1));
textArea2.setText(r.get(2));
textArea3.setText(r.get(3));
textArea4.setText(r.get(4));
mediaPlayerComponent.getMediaPlayer().setPosition(Float.parseFloat(r.get(5)));
mediaPlayerComponent2.getMediaPlayer().setPosition(Float.parseFloat(r.get(6)));
}
}
});

最佳答案

仅解析您的 XML 文件一次,并声明一个整数来跟踪当前显示的位置

    List<List<String>> obj = XmlToObject.main();
int displayedPositionIndex = 0;

然后在您的 ActionListener 上,增加计数器并显示下一个位置

load.addActionListener(new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
displayedPositionIndex++;
if(displayedPositionIndex >= obj.size()) {
displayedPositionIndex = 0; // to loop back to first after last position
}
setPosition(displayedPositionIndex);
}
});

我使用这个实用方法让事情变得更清晰

private void setPosition(int index) {
List<String> positionData = obj.get(index);
textArea.setText(positionData.get(0));
textArea1.setText(positionData.get(1));
textArea2.setText(positionData.get(2));
textArea3.setText(positionData.get(3));
textArea4.setText(positionData.get(4));
mediaPlayerComponent.getMediaPlayer().setPosition(Float.parseFloat(positionData.get(5)));
mediaPlayerComponent2.getMediaPlayer().setPosition(Float.parseFloat(positionData.get(6)));
}

注意

在您的 XmlToObject 中,最好使用 List<List<String>>ArrayList<ArrayList<String>> (如果可以的话,请始终使用该界面):

class XmlToObject {

public static List<List<String>> main() {
List<List<String>> positions = new ArrayList<>();

try {
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document d = db.parse("/path/to/savedPos.xml");
XPath xp = XPathFactory.newInstance().newXPath();

NodeList nl = (NodeList) xp.compile("//savedPosition").evaluate(d, XPathConstants.NODESET);
System.out.println("number of saved positions " + nl.getLength());

for (int i = 0; i < nl.getLength(); i++) {
String a = (xp.compile("./nBehaviour").evaluate(nl.item(i)));
String b = (xp.compile("./aBehaviour").evaluate(nl.item(i)));
String c = (xp.compile("./gap").evaluate(nl.item(i)));
String d1 = (xp.compile("./forces").evaluate(nl.item(i)));
String e = (xp.compile("./findings").evaluate(nl.item(i)));
String f = (xp.compile("./position1").evaluate(nl.item(i)));
String g = (xp.compile("./position2").evaluate(nl.item(i)));

List<String> savedPosition = Arrays.asList(a, b, c, d1, e, f, g);
positions.add(savedPosition);
}

} catch (Exception e) {
e.printStackTrace();
}

return positions;
}
}

关于java - 将数据从 XML 返回到 UI,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/49263560/

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