python - 我将工作代码复制并粘贴到我的 IDE 中——现在 Python 抛出了大量错误

Question

我将代码复制并粘贴到我的 IDE (TextWrangler) 中。现在，当我尝试运行我的代码时，我收到大量关于缩进和无效语法的随机错误。

在我将代码从一个 Django View 复制并粘贴到另一个之前，代码运行良好。我几乎 100% 确定代码在我的新 View 中仍然是正确的，但是，每次它运行时，我都会遇到大量与缩进和无效语法相关的错误(甚至像 ''' 这样的多行注释会触发“无效语法”在第 234 行“错误。

我试过将 IDE 切换到 sublime，甚至退格所有缩进，然后重新制表，但无济于事。每次我修复一行中的“错误”时，都会在另一行中创建一个新错误。

我的代码在下面，请告诉我有关如何修复的任何想法。

@require_POST   
def pay(request):


if request.method == 'POST':
    form = CustomerForm(request.POST)

    if form.is_valid(): 
    # If the form has been submitted...
    # All validation rules pass


        #get the customer by session'd customer_id
        c = get_object_or_404(Customer, pk = request.session['customer_id'])

        #assign shipping info from POST to the customer object
        c.first_name = request.POST['first_name']
        c.last_name = request.POST['last_name']
        c.street_address = request.POST['street_address']
        c.city = request.POST['city']
        c.state = request.POST['state']
        c.zip = request.POST['zip']

        #assign email info from POST to the customer object

        c.email_address = request.POST['email_address']

        stripe.api_key = REDACTED

        # Get the credit card details submitted by the form
        token = request.POST['stripeToken']


        #tries to save the newly added form data. 
        try:
            #save the new customer object's data
                c.save()

##########   THIS HANDLES CREATING A NEW STRIPE PAYMENT ################                    

    # Create a Customer 
        try:
            customer = stripe.Customer.create(
            card=token,
            plan="monthly",
            email= c.email_address)
            #need to save customer's id (ex: c.stripe_id = token.id)

            #if there's a token error   
        except stripe.error.InvalidRequestError, e:
            pass

        #if the card is declined by Stripe

        except stripe.error.CardError, e:
            body = e.json_body
            err  = body['error']

            print "Status is: %s" % e.http_status
            print "Type is: %s" % err['type']
            print "Code is: %s" % err['code']
            # param is '' in this case
            print "Param is: %s" % err['param']
            print "Message is: %s" % err['message']

        except stripe.error.AuthenticationError, e:
        # Authentication with Stripe's API failed
        # (maybe you changed API keys recently)
            pass

        except stripe.error.APIConnectionError, e:

        # Network communication with Stripe failed
            pass

        except stripe.error.StripeError, e:
        # Display a very generic error to the user, and maybe send
        # yourself an email
            pass

        except Exception, e:
        # Something else happened, completely unrelated to Stripe
            pass    

        return render(request, 'shipment/confirm.html', {'date' : 'April 15, 2014'})


            #passes the context to the template for confirming the customer's data
            #context = { 'email_address' : c.email_address, 'first_name' : c.first_name,
            #   'last_name' : c.last_name, 'street_address' : c.street_address, 
            #   'city' : c.city, 'state' : c.state, 'zip' : c.zip, }

            #return render(request, 'shipment/pay.html', context)

        #If there is a duplicate email it redirects the user back to the form with no error message.  




#If anything else happens, it redirects the user back to the form.      
else:
    form = CustomerForm() # An unbound form
    return render(request, 'shipment/createAccount.html', { 'form': form } )

Answer 1

这是您在我的编辑器中的代码的几个屏幕截图，其中制表符(设置为 4)和空格字符以红色显示。如您所见，它在很多行上包含了两者的大杂烩。 Python 对空格非常敏感，因此保持一致很重要。这通常通过将您的编辑器配置为始终将制表符转换为 n 个空白字符来处理(反之亦然，但通常首选前者)。

要解决您的问题，请使用一种方法重新缩进所有内容。我的编辑器还有一个 convert-tabs-to-spaces 命令，可以先使用它来稍微简化任务。