linux - 如果在一行中找到大写字母则拆分行

Question

我需要一个正则表达式，如果找到大写字母，它可以拆分行。

例子:-

line1 = JOHN levin have fun RAJESH is a good person SAM was ok

期望输出如下

line1 = JOHN levin have fun
RAJESH is a good person
SAM was ok.

Answer 1

是你想要的吗？

$ line1='JOHN levin have fun RAJESH is a good person SAM was ok'
$ sed 's/[A-Z]\+/\n&/g' <<< $line1

JOHN levin have fun
RAJESH is a good person
SAM was ok

请注意，在 JOHN 之前添加了一个换行符，因为它符合您的要求。避免它是另一个问题。另外你的要求是:

I need a regex which could split the lines if Uppercase letter found.

所以预期的输出应该是:

$ sed 's/\([A-Z]\)/\n\1/g' <<< $line1

J
O
H
N levin have fun
R
A
J
E
S
H is a good person
S
A
M was ok