linux - 执行 Linux bash 脚本时出现错误

Question

执行文件“handoff”中的脚本时出现以下错误:

sh handoff
'andoff: line 5: syntax error near unexpected token `do
'andoff: line 5: `  do

文件内容如下:

cat handoff
while [ 1 ]; do
   credencemove
  k=0
  for n in `cat credencemove.txt`
  do
    status[$k]=$n
    k=`expr $k + 1`
  done
  for m in `cat logsequence.lst`
  do
    status[$k]=$m
    k=`expr $k + 1`
  done
   ls -lrt | grep arch_credence_1 | tail -1 | cut -c 68- | tr -d 'ah_.log.gz' | cut -c -5 > credencereceived.txt
  for o in `cat credencereceived.txt`
  do
    status[$k]=$o
    k=`expr $k + 1`
  done
   clear
   tput bold
   echo "         Received Applied Moved"
   echo "         ========================"
   echo " "
   echo " Credence1 -> ${status[6]} \c"
   echo "  ${status[3]} \c"
   echo "  ${status[0]}"
   tput rmso
   echo " "
   echo "Waiting 15 Minuites for applying further logs..."
   echo "Press ctrl + c to exit"
   sleep 900
done

Answer 1

您的 bash 脚本中有回车符 (\r)，就像该脚本是在 Windows 文本编辑器上创建的一样。

使用 dos2unix 清理您的脚本。