python - Django 1.6 名称选择未定义

Question

我试图在我的模板中显示下拉菜单，但出现以下错误

File "forms.py" in DropdownSelectionForm
  101.     selection = forms.ChoiceField(choices=MY_CHOICES, widget = Select)

Exception Type: NameError at /
Exception Value: name 'Select' is not defined

这是我试图显示表单的模板

 <form action="/doclistings/" method="post" >{% csrf_token %}
            <select class="form-control" id="s1" NAME="selection">
              <option><b>Find a Doctor...</b></option>
              {% for value, text in form.selection.field.choices %}
                <option value="{{ value }}">{{ text }}</option>
              {% endfor %}
            </select>

这里是forms.py

MY_CHOICES = (
    ('Dermatologist', 'Dermatologist'),
    ('Dentist', 'Dentist'),
    ('Opthalmologist', 'Opthalmologist'),
)

class DropdownSelectionForm(forms.Form):
    selection = forms.ChoiceField(choices=MY_CHOICES, widget = Select)

Answer 1

与 Python 中的其他任何内容一样，您需要正确引用对象。在这种情况下，Select 通过表单模块提供，与 ChoiceField 完全一样。

selection = forms.ChoiceField(choices=MY_CHOICES, widget=forms.Select)