linux - 删除包含多行字符串中单词的内容

Question

我有以下多行字符串。我不能把它写成一行，因为它来自命令输出。例如:

my $myString = "Lorem Ipsum is simply dummy text of the printing and typesetting industry. 
Lorem Ipsum has been the industry's standard dummy text ever since the 1500s,
when an unknown printer took a galley of type and scrambled it to make a 
type specimen book. It has survived not only five centuries, but also 
the leap into electronic typesetting, remaining essentially unchanged. 
It was popularised in the 1960s"

我想去掉包括“scrambled”这个词在内的内容

我试过下面但似乎不起作用。

if($myString =~ 's/.*(scrambled)//s')
{
  print "Match:   <$&>\n";
}

Answer 1

#!/usr/bin/perl
use strict;
use warnings;

my $myString = "Lorem Ipsum is simply dummy text of the printing and typesetting industry. 
Lorem Ipsum has been the industry's standard dummy text ever since the 1500s,
when an unknown printer took a galley of type and scrambled it to make a 
type specimen book. It has survived not only five centuries, but also 
the leap into electronic typesetting, remaining essentially unchanged. 
It was popularised in the 1960s";

$myString =~ s/.*\bscrambled\b//s;

print $myString;

Demo