java - 创建 Xmpp 连接并传递实例而无需重新创建的最佳方法

Question

我有一个名为 XmppChatManager 的类(class)其中具有所有必要的方法，例如 initializingConnection()和sendOneToOneMessage() ，其他需要使用这个类的类需要做这样的事情:

XmppChatManager xmppchatmanager = new XmppChatManager(this, userId, password);

runOnUiThread(new Runnable() {
                public void run() {
                    Thread thread = new Thread(){
                        public void run(){
                            try {
                                xmppchatmanager.initializingConnection();
                            } catch (IOException e) {
                                e.printStackTrace();
                            } catch (XMPPException e) {
                                e.printStackTrace();
                            } catch (SmackException e) {
                                e.printStackTrace();
                            }
                        }
                    };
                    thread.start();
                }
            });

This is pretty much all I need to get started, the issue i'm having is when I try calling the sendOneToOneMessage() method from the chatClass, I have to get the instance of the created connection because Smack Error will occur if I try reconnecting when the connection is already initiated! So I need to make available the instance of that initiated connection by creating a method called getInstance() I guess this might be simple but I have tried but I'm not getting it. Any one with better way of handling such?

Answer 1

让你的xmppchatmanager成为单例，例如

public class XmppChatManager{
   static class Loader{
        static XmppChatManager sInstance = new XmppChatManaget();
   }

   public static XmppChatManager getInstance(){
        return Loader.sInstance;
   }
}