python - 将元素拆分为python中的新列表

Question

我的列表是这样的:

['Jeoe Pmith H 158.50\n', 'Ppseph Ksdian h 590.00\n', 'll Mos K 89.0\n', 'Wncy Bwn  j -97.0\n', 'May KAss S  33.58\n', 'Ai Hami s 670.0\n', 'Age Karn J 674.50\n', 'Loe AIUms s 87000.0\n', 'karl Marx J 67400.9\n', 'Joeh Stig S 34.8\n']

它如何拆分这个列表中的元素，并将其分成 3 个新列表，如下所示:

[' Jeoe Pmith', 'Ppseph Ksdian', ....'Joeh Stig']

['H' , 'h', 'K', .....'S']

['158.50', '590.00'....'34.8'] #(for this list, getting rid of \n as well)

谢谢!!

Answer 1

怎么样:

>>> l = ['Jeoe Pmith H 158.50\n', 'Ppseph Ksdian h 590.00\n', 'll Mos K 89.0\n', 'Wncy Bwn  j -97.0\n', 'May KAss S  33.58\n', 'Ai Hami s 670.0\n', 'Age Karn J 674.50\n', 'Loe AIUms s 87000.0\n', 'karl Marx J 67400.9\n', 'Joeh Stig S 34.8\n']
>>> zip(*(el.rsplit(None, 2) for el in l))
[('Jeoe Pmith', 'Ppseph Ksdian', 'll Mos', 'Wncy Bwn', 'May KAss', 'Ai Hami', 'Age Karn', 'Loe AIUms', 'karl Marx', 'Joeh Stig'), ('H', 'h', 'K', 'j', 'S', 's', 'J', 's', 'J', 'S'), ('158.50', '590.00', '89.0', '-97.0', '33.58', '670.0', '674.50', '87000.0', '67400.9', '34.8')]

(它给出了一个元组列表而不是列表列表，但如果你关心它，这很容易改变。)