linux - 通过 shell 脚本输出编辑 .csv 文件

Question

我有一个脚本，它将 .csv 文件作为输入并逐行运行

kma210,projects.kma210
kma215,projects.kma215_2
KMA3xx,projects.kma3xx
KMI7,projects.kmi7

以上是.csv 文件的示例。我为每一行运行了两种类型的进程(例如:abc_process 和 xyz_process)。

现在我的要求是一旦脚本运行一行，输出即成功/失败应该打印在同一个文件的第三列 (abc_process) 和第四列 (xyz_process)。

示例请看这里:

kma210,projects.kma210,success,success
kma215,projects.kma215_2,fail,success
KMA3xx,projects.kma3xx,success,fail
KMI7,projects.kmi7,fail,fail

谁能推荐一下？

Answer 1

我认为您要实现的目标就是此类。

从您的输入文件 (input.csv)，使用如下脚本:-

#!/bin/bash

while IFS=',' read -r col1 col2
do
    # The below two read commands are to process the success/fail status
    # string as you indicated. If you are receiving a string of the below 
    # form, from an external bash command; you need to use process-substitution 
    # as

    # IFS= read -r _ p1Status <<(p1Command)
    # IFS= read -r _ p1Status <<(p2Command)

    IFS= read -r _ p1Status <<<"abc success"
    IFS= read -r _ p2Status <<<"xyz fail"

    # The below printf just prints the output as you need to stdout
    # to create a .csv out of it, append it to a new file as

    # printf "%s,%s,%s,%s\n" "$col1" "$col2" "$p1Status" "$p2Status" >> output.csv

    printf "%s,%s,%s,%s\n" "$col1" "$col2" "$p1Status" "$p2Status"
done<input.csv

上述命令写入stdout，产生如下输出

kma210,projects.kma210,success,fail
kma215,projects.kma215_2,success,fail
KMA3xx,projects.kma3xx,success,fail
KMI7,projects.kmi7,success,fail

您可以使用 >>> 运算符将其附加到我注释掉的行的文件中。或者，如果您想要单个文件并替换原始文件。添加一行

mv -v output.csv input.csv 

作为脚本的最后一行。