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java - 如何在第一个对话框上调用removeView()以显示第2个对话框

转载 作者:太空宇宙 更新时间:2023-11-04 10:26:38 26 4
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我正在使用一个应用程序,该应用程序涉及应一个接一个出现的对话框。我的意思是,当我单击第一个对话框的肯定按钮时,它应该弹出另一个第二个对话框。我面临的问题是第二个对话框,第二个对话框不会弹出,它会导致应用程序崩溃。

我收到一条错误消息“java.lang.IllegalStateException:指定的子项已经有父项。您必须首先在子项的父项上调用removeView()。”

public static void showBusinessOrPrivateStartDialog(final Context context, final CallLogEntry call)
{
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M)
{
// If new version of android, then check permission
if (!Settings.canDrawOverlays(context))
{
Log.e(TAG, "Permission Denied: Draw overlays (for popup)");
return;
}
}

LayoutInflater inflater = (LayoutInflater)context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
//View view = inflater.inflate(R.layout.dialog_call_type, null);

AlertDialog.Builder builder = new AlertDialog.Builder(context, Theme_Material_Light_Dialog_Alert);

builder.setTitle("Was this a private or a business call?");
builder.setMessage("Please select a call type");
builder.setIcon(R.drawable.ic_deviceinsight);
builder.setCancelable(true);
//builder.setView(view);

builder.setOnCancelListener(new DialogInterface.OnCancelListener() {
@Override
public void onCancel(DialogInterface dialog) {
// Occurs when user cancels the dialog, or clicks somewhere else in the screen or presses the back button
Log.i(TAG, "cancelled");

saveCallEntry(context, call, CLASSIFICATION_TYPE_BUSINESS, "", true, "");
}
});

builder.setPositiveButton("Business", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
CallClassification.showBusinessCallPopup(context, call);
}
});
builder.setNegativeButton("Private", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
saveCallEntry(context, call, CLASSIFICATION_TYPE_PRIVATE, "", false, "");
}
});

AlertDialog dialog = builder.create();
// Rather use something like TYPE_SYSTEM_ALERT, if possible.
dialog.getWindow().setType(WindowManager.LayoutParams.TYPE_SYSTEM_ALERT); // TYPE_SYSTEM_ERROR
dialog.show();
}

这是第二个对话框的第二种方法,我的应用程序在dialog.show上崩溃

public static void showBusinessCallPopup(final Context context, final CallLogEntry call)
{
// NEW NRF
if (AppPreferences.isNRF(context)) {
CallItem callItem = saveCallEntry(context, call, CLASSIFICATION_TYPE_BUSINESS, "", false, "");

// SHOW NEW FORM
Intent intent = new Intent(context, CallClassificationFormActivity.class);
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
EventBus.getDefault().postSticky(callItem);
context.startActivity(intent);

return;
}

if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M)
{
// If new version of android, then check permission
if (!Settings.canDrawOverlays(context))
{
Log.e(TAG, "Permission Denied: Draw overlays (for popup)");
return;
}
}

LayoutInflater inflater = (LayoutInflater)context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
View view = inflater.inflate(R.layout.dialog_call_details, null);

AlertDialog.Builder builder = new AlertDialog.Builder(context, Theme_Material_Light_Dialog_Alert);

String toOrFrom = call.Type == CallLog.Calls.INCOMING_TYPE ? "from" : "to";

//builder.setTitle("Business call");
builder.setCustomTitle(view);
//builder.setMessage("Please enter reference details for the call " + toOrFrom + " " + call.Number);
//builder.setIcon(R.drawable.ic_deviceinsight);
builder.setCancelable(true);
builder.setView(view);

final EditText etReference = (EditText)view.findViewById(R.id.etReference);
final EditText etComment = (EditText)view.findViewById(R.id.etComment);

builder.setPositiveButton("Confirm", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {

String reference = etReference.getText().toString();
String comment = etComment.getText().toString();

saveCallEntry(context, call, CLASSIFICATION_TYPE_BUSINESS, reference, false, comment);
}
});
builder.setOnCancelListener(new DialogInterface.OnCancelListener() {
@Override
public void onCancel(DialogInterface dialog) {
Log.i(TAG, "cancelled");
}
});

AlertDialog dialog = builder.create();
dialog.getWindow().setType(WindowManager.LayoutParams.TYPE_SYSTEM_ALERT); // TYPE_SYSTEM_ERROR
dialog.show();
}

这是我的 xml。我在这篇文章中包含了 xml,因为我在某处读到了文本框的高度和宽度的定义方式可能会导致问题。

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:app="http://schemas.android.com/apk/res-auto"
xmlns:tools="http://schemas.android.com/tools"
android:id="@+id/layout"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:orientation="vertical"
android:paddingLeft="5dp"
android:paddingRight="5dp"
android:paddingTop="5dp"
tools:context=".calls.CallClassification">

<TextView
android:id="@+id/tvMessage"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:layout_marginBottom="5dp"
android:padding="5dp"
android:text="Please enter reference details for the call "
android:textColor="@color/colorPrimaryDark"
android:textSize="16sp"/>

<AutoCompleteTextView
android:id="@+id/etReference"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:backgroundTint="@color/colorAccent"
android:hint="Matter Code *"
android:imeOptions="actionNext"
android:inputType="text"
android:maxLength="255"
android:text=""
android:textColor="@color/colorPrimary"
android:textColorHint="@color/colorTextHint"
android:textSize="14sp"/>

<CheckBox
android:id="@+id/cbBillable"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:layout_marginLeft="5dp"
android:layout_marginRight="5dp"
android:button="@null"
android:buttonTint="@color/colorAccent"
android:checked="true"
android:drawableRight="?android:attr/listChoiceIndicatorMultiple"
android:paddingBottom="3dp"
android:paddingTop="3dp"
android:text="Billable"
android:textColor="@color/colorPrimaryDark"
android:textSize="14sp"/>

<EditText
android:id="@+id/etComment"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:backgroundTint="@color/colorAccent"
android:hint="Enter comment"
android:imeOptions="actionDone"
android:inputType="text"
android:lines="1"
android:maxLength="1000"
android:maxLines="4"
android:minLines="1"
android:text=""
android:textColor="@color/colorPrimary"
android:textColorHint="@color/colorTextHint"
android:textSize="14sp"/>

<LinearLayout
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="horizontal">

<Button
android:id="@+id/bCancel"
style="@style/Widget.AppCompat.Button.Borderless.Colored"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_weight="1"
android:text="Cancel"/>

<Button
android:id="@+id/bOk"
style="@style/Widget.AppCompat.Button.Borderless.Colored"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_weight="1"
android:text="GO"/>
</LinearLayout>


</LinearLayout>

最佳答案

听了你的经历后,我可以想到另一个解决方案。不要在每个方法中声明 AlertDialog 变量,而是声明一个全局变量,这样您就可以确保在任何实例中只显示一个对话框。

声明时,使

AlertDialog dialog = null;

在类里面然后在,

    showBusinessOrPrivateStartDialog() {
if(dialog == null) {
dialog = build.create();
}
}


builder.setPositiveButton("Business", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
dialog.dismiss();
CallClassification.showBusinessCallPopup(context, call);
}
});

builder.setOnDismissListener(new OnDismissListener() {
public void onDismiss() {
dialog = null;
}
}

然后再次在 showBusinessCallPopup() 中,

if(dialog == null) {
dialog = build.create();
}

希望这对您有帮助。

关于java - 如何在第一个对话框上调用removeView()以显示第2个对话框,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/50464865/

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