python - 下面脚本的 while 循环

Question

我目前正在创建一个游戏，它会一遍又一遍地循环，直到您猜对数字为止。

我遇到的问题是正确执行循环命令。我想进行 while 循环，但对于脚本的某些部分，我可以让它工作。如果我使用“while true”循环，if 语句的打印命令会一遍又一遍地重复，但如果我使用任何符号(<、>、<=、>= 等)，我似乎无法让它工作在 elif 语句上。代码可以在下面找到:

#GAME NUMBER 1: GUESS THE NUMBER
from random import randint
x = randint(1,100)
print(x) #This is just here for testing
name = str(input("Hello there, my name's Jarvis. What's your name?"))
print("Hello there ",name," good to see you!")
num = int(input("I'm thinking of a number between 1 and 100. can you guess which one it is?"))
attempt = 1
while  
    if num == x:
        print("Good job! it took you ",attempt," tries!")
        num + 1
    elif num >= x:
        print("Too high!")
        attempt = attempt + 1      
    elif num <= x:
        print("Too low!")
        attempt = attempt + 1
    else:
        print("ERROR MESSAGE!")

感谢任何帮助。

Answer 1

您可以在 while 中使用 bool 值:

from random import randint
x = randint(1,100)
print(x) #This is just here for testing
name = str(input("Hello there, my name's Jarvis. What's your name?"))
print("Hello there ",name," good to see you!")
attempt = 1
not_found = True
while not_found:
    num = int(input("I'm thinking of a number between 1 and 100. can you guess which one it is?"))
    if num == x:
        print("Good job! it took you ",attempt," tries!")
        not_found = False
    elif num > x: #Don't need the equals
        print("Too high!")
    elif num < x: #Don't need the equals
        print("Too low!")
    else:
        print("ERROR MESSAGE!")
    attempt = attempt + 1