linux - 使 curl 命令 shell 脚本 centOS 超时

Question

checkServer(){
    response=$(curl --connect-timeout 10  --write-out %{http_code} --silent --output /dev/null localhost:8080/patuna/servicecheck)

    if [ "$response" = "200" ];
        then echo "`date --rfc-3339=seconds` -  Server is healthy, up and running"
        return 0
    else
        echo "`date --rfc-3339=seconds` -  Server is not healthy(response code - $response ), server is going to restrat"
        startTomcat
    fi
}

在这里，我想使 curl 命令超时，但它不起作用。在centos7 Shell scrit中。我只需要做的就是使 curl 命令超时 错误代码是 curl:选项 --connect-timeout=: 未知

Answer 1

checkServer(){
        response=$(curl --max-time 20 --connect-timeout 0  --write-out %{http_code} --silent --output /dev/null localhost:8080/patuna/servicecheck)

        if [ "$response" = "200" ];
           then echo "`date --rfc-3339=seconds` -  Server is healthy, up and running"
           return 0
        else
           echo "`date --rfc-3339=seconds` -  Server is not healthy(response code - $response ), server is going to restrat"
           startTomcat
        fi
}