linux - 从 shell 脚本中的文件中逐行读取并显示最低的 2 个值

Question

我创建了一个游戏，用户猜测由程序随机创建的数字，猜对成功后程序询问用户名并将用户名和分数存储在文件中。现在我想打印得分最低的 3 名玩家的姓名和得分。

range=129
randNum=`expr $RANDOM % $range`     # generates a random number between 0 and 128

score=0

printf "Enter a number: "
read num

while [ $randNum -ne $num ];
do

    if [ $num -lt $randNum ]; then
        printf "Low guess"
        score=`expr $score + 1`
    else
        printf "High guess"
        score=`expr $score + 1`
    fi

    printf "\nEnter a number: "
    read num
done

read  -p "Enter your name: " name

FILE="gameScores.txt"
echo "$name     $score" >> $FILE

readFile=`cat $FILE`

# what should i do furthur to read from file sequentially and apply a condition for lowest scores

Answer 1

尝试

sort -k 2,2n gameScores.txt | head -3

这将根据第二个字段中的分数对您的分数文件进行排序。然后您只需打印前 3 个分数，这应该是您的最低分数。

希望这对您有所帮助。