python - 替换列表中一之间的零

Question

假设我有一个如下所示的列表。您如何遍历列表并替换以零为界的零，其中零之间的长度可以变化？

输入:

mylist = [0,0,0,1,0,0,0,0,1,0,0,0,0,1,0,0,1,0,0]

输出:

mylist = [0,0,0,1,1,1,1,1,1,0,0,0,0,1,1,1,1,0,0]

Answer 1

我认为您可以分两个阶段完成此操作:

1. 首先，我们获取指示的索引；和
2. 我们一次拿两个，然后用一个填满这些。

喜欢:

# obtain an iterable of the indices of the ones
ones = iter([i for i,x in enumerate(mylist) if x == 1])

# for every pair of indices
for i0,i1 in zip(ones,ones):
    # iterate over the range
    for j in range(i0+1,i1):
        # and assign 1 to these indices
        mylist[j] = 1

这会产生:

>>> mylist
[0, 0, 0, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 1, 1, 1, 1, 0, 0]