java - 无法点击 android.widget.ImageButton

Question

我尝试过以下定位器

driver.findElement(By.xpath("//android.widget.ImageButton[@content-desc='Open navigation drawer']")).click();
or
driver.findElement(By.xpath("//android.widget.ImageButton[@index='0'])")).click();
or
driver.findElementByXPath("(//android.view.ViewGroup)[1]").click();

下载= Link

Not able to click on image button.

@Test
public AndroidDriver<AndroidElement> Loging() throws MalformedURLException, InterruptedException {

    File file = new File("src/test/java", "opentap-v1.1-28012019.apk");
    DesiredCapabilities capabilities = new DesiredCapabilities();
    capabilities.setCapability(MobileCapabilityType.DEVICE_NAME, "Pixel_C_Edited_API_28");
    capabilities.setCapability(MobileCapabilityType.APP, file.getAbsolutePath());
    AndroidDriver<AndroidElement> driver = new AndroidDriver<>(new URL("http://127.0.0.1:4723/wd/hub"),
            capabilities);
    driver.manage().timeouts().implicitlyWait(20, TimeUnit.SECONDS);
    driver.findElement(By.id("com.opentap:id/btn_go")).click();
    driver.findElement(By.id("username")).clear();
    driver.findElement(By.id("username")).sendKeys("kaustubh.patil");
    driver.findElement(By.id("password")).clear();
    driver.findElement(By.id("password")).sendKeys("opentapuat");
    driver.findElement(By.id("rememberMe")).click();
    driver.findElement(By.id("kc-login")).click();
    // driver.findElement(By.id("com.opentap:id/btn_go")).click();
    // Thread.sleep(10000);
    // driver.findElement(By.xpath("//android.widget.ImageButton[@index='0'])")).click();
    // driver.findElementByXPath("(//android.view.ViewGroup)[1]").click();

    // WebDriverWait wait = new WebDriverWait(driver, 25);
    // WebElement element =
    // wait.until(ExpectedConditions.elementToBeClickable(By.id("com.opentap:id/add")));
    /*
     * try { Thread.sleep(1000); WebDriverWait wait = new WebDriverWait(driver, 30);
     * wait.until(driver .findElement(By.
     * xpath("//android.widget.ImageButton[@content-desc='Open navigation drawer']")
     * )); } catch (Throwable error) {
     * Assert.fail("Timeout waiting for Page Load Request to complete."); }
     */
    driver.manage().timeouts().setScriptTimeout(25, TimeUnit.SECONDS);
    driver.findElement(By.xpath("//android.widget.ImageButton[@content-desc='Open navigation drawer']")).click();
    return driver;
}

Answer 1

您可以使用触摸操作类和指针来执行您的要求。使用下面的代码片段，它将完美地适用于每个具有抽屉式导航栏的应用程序(我已经尝试过许多应用程序，工作得很好)。

TouchAction action = new TouchAction(driver);
action.tap (10, 100).perform();

这里，10是X指针，100是Y指针。为什么我将 x 指定为 10 是因为，drawar 图像将位于 0-15 范围之间，并且您还必须确保 Drawar 位置(对于某些应用程序，它可能位于右侧，然后您必须相应地给出坐标)。