python - 打开名称文件

Question

当我尝试打开该函数的文件时，我没有得到所有的名字。我想得到这个:

Smith, Joe,9911991199,smithjoe9,99,88,77,66
Ash, Wood,9912334456,ashwood,11,22,33,44
Full, Kare,9913243567,fullkare,78,58,68,88

但是我在测试函数时得到了这个:

['Ash, Wood,9912334456,ashwood,11,22,33,44\n', 'Full, Kare,9913243567,fullkare,78,58,68,88\n']

谁能帮我解决这个问题？我怎样才能包括第一个人的名字？

def open_grades_file(filename):
    '''(str) -> file

    Open filename, read past its one-line header and
    return the open file.
    '''
    file = open(filename, 'r')
    file.readline()
    for line in file:
        line.rstrip('\n')
        return file

Answer 1

如果您希望函数实际对应于它的文档字符串，请使用:

def open_grades_file(filename):
    '''(str) -> file

    Open filename, read past its one-line header and
    return the open file.
    '''
    file = open(filename, 'r')
    file.readline()
    return file

但这是一件很奇怪的事情，像这样的函数会更像 pythonic:

def read_grade_lines(path):
    with open(path) as f:
        for line in f.readlines():
            yield line.strip()