java - 多个字符串输入，退出循环......没有数组

Question

所以我更新了我的代码，但它做了一件非常奇怪的事情。当输入两个输入时，它返回最长和最短的变量以及其余变量。但是，当输入两个以上时，它会返回最长的...很棒...但对于最短的，它只返回比最长的单词短的单词，而不是输入的最短字符串...发生了什么:(

import java.util.Scanner;
public class StringReporting
{
    public static void main (String[] args)
    {
        Scanner in = new Scanner (System.in);
        String word ="";
        String words = "";
        String result ="";
        int count = 0;
        int shortest = 1;
        int longest = 1;
        int sumOfLengths = 0;
        double averageLength = 0;
        String shortestWord = "";
        String longestWord = "";
        while (!word.equals("x"))
        {
            count ++;
            System.out.println ("Please enter String " + count + ", enter x 
            to exit: ");
            word = in.nextLine();
            words  += "String " + count + ": " + word + "\n";
            sumOfLengths += word.length();
            if (word.length()>longest)
            {
                longest= word.length();
                longestWord = word;
            }   
            else if(word.length()> shortest && word.length() < longest)
            {
                shortest = word.length();
                shortestWord = word;
            }   


        }


        averageLength = (sumOfLengths-1) / (count-1);
        System.out.println ("shortest string entered: 
        " + shortestWord + ", with a length of: " + shortest);
        System.out.println ("longest string entered: " 
        + longestWord + ", with a length of: " + longest);
        System.out.println (" sum of all lengths: " + 
        (sumOfLengths-1));
        System.out.println ("number of strings: " + count);
        System.out.println ("average string length : " + averageLength);

Answer 1

这听起来像是学校练习，所以我会尽力帮助您，但不会明确给出答案。

您只需要一个循环，并且在输入所有单词后不应再次循环所有单词。输入“x”后，应该已经计算出要打印的结果(或者需要最少的整理，例如计算平均值)。您可以在末尾打印多个值，无需将其全部放入 1 个字符串中。

如果您需要更多帮助，请随时询问!