Java - 查找数组中的元素

Question

我目前正在尝试找出如何搜索数组以查找数组中的特定元素。用户将输入他们想要查找的名字，我的程序应该将他们所坐的座位返回给用户。添加乘客是通过另一种方法完成的。因此，如果我有一个叫“Tim Jones”的人坐在 5 号座位上，如果我使用此方法，我会输入“Tim Jones”，程序应该告诉我 Tim Jones 坐在 5 号座位上。

我得到的当前输出只是 else 语句，无论我如何尝试都找不到乘客。有小费吗？提前致谢。

private static void findPassengerSeat(String airplaneRef[]) {
    String passengerName;
    Scanner input = new Scanner(System.in);
    System.out.println("Enter passenger's name."); // asks user for passenger name.
    passengerName = input.next(); // user input stored under variable passengerName.
    for (int i = 0; i < airplaneRef.length; i++) { // for i, if i is less than the length of the array airplaneRef, increment i.
        if (airplaneRef[i].equalsIgnoreCase(passengerName)) { // iterates through all elements in the array, ignoring case sensitivity and looks for the passenger.
            int seat = i;
            System.out.println(passengerName + " is sitting in seat s" + seat); // prints name of passenger and what seat they are sitting in.
        } else {
            System.out.println("Passenger not found.");
            break;
        }
    }
}

Answer 1

您应该删除 else，否则您只会评估数组的第一个索引并传递所有其余索引。

以下内容应该发挥其魅力:您基本上会遍历所有乘客的列表，并且只有当没有一个与输入相对应时，您才会声明找不到该乘客。

for (int i = 0; i < airplaneRef.length; i++) { // for i, if i is less than the length of the array airplaneRef, increment i.
    if (airplaneRef[i].equalsIgnoreCase(passengerName)) { // iterates through all elements in the array, ignoring case sensitivity and looks for the passenger.
        int seat = i;
        System.out.println(passengerName + " is sitting in seat s" + seat); // prints name of passenger and what seat they are sitting in.
        return;
    }
}
System.out.println("Passenger not found.");