java - 如何从地理编码器获取城市名称？

Question

在 Android 中(Java 或 Kotlin 都可以)如何从经度和纬度获取城市名称？

下面我编写了一个显示地址数据的函数。我想修改它，以便它返回城市名称:

private fun getCity(context: Context, latitude: Float, longitude: Float) {
    val gcd = Geocoder(context, Locale.getDefault())
    val addresses = gcd.getFromLocation(latitude.toDouble(), longitude.toDouble(), 1)
    Log.d("-----", "-----")
    Log.d("latitude", latitude.toString())
    Log.d("longitude", longitude.toString())
    if (addresses.size > 0) {
        val locality = addresses[0].locality
        if (locality != null) {
            Log.d("locality", locality.toString())
        }
        val adminArea = addresses[0].adminArea
        if (adminArea != null) {
            Log.d("adminArea", adminArea.toString())
        }
        val subAdminArea = addresses[0].subAdminArea
        if (subAdminArea != null) {
            Log.d("subAdminArea", subAdminArea.toString())
        }
        val subLocality = addresses[0].subLocality
        if (subLocality != null) {
            Log.d("subLocality", subLocality.toString())
        }
        val thoroughfare = addresses[0].thoroughfare
        if (thoroughfare != null) {
            Log.d("thoroughfare", thoroughfare.toString())
        }
        val subThoroughfare = addresses[0].subThoroughfare
        if (subThoroughfare != null) {
            Log.d("subThoroughfare", subThoroughfare.toString())
        }
        val extras = addresses[0].extras
        if (extras != null) {
            Log.d("extras", extras.toString())
        }
        val premises = addresses[0].premises
        if (premises != null) {
            Log.d("premises", premises.toString())
        }
        val postalCode = addresses[0].postalCode
        if (postalCode != null) {
            Log.d("postalCode", postalCode.toString())
        }
        val featureName = addresses[0].featureName
        if (featureName != null) {
            Log.d("featureName", featureName.toString())
        }
        val getAddressLine0 = addresses[0].getAddressLine(0)
        if (getAddressLine0 != null)
            Log.d("getAddressLine0", getAddressLine0.toString())
        for (i in 0 until addresses[0].maxAddressLineIndex) {
            Log.d("getAddressLine($i)", addresses[0].getAddressLine(i).toString())
        }
    }
}

如果我运行 getCity(context, 53.7f, -1.506f)，featureName 包含正确的城市名称 Wakefield。

如果我运行 getCity(context, 53.801f, -1.549f)，featureName 现在包含街道名称 Portland Place。 getAddressLine(0) 返回 Portland Place, 5 Calverley St, Leeds LS1 3DA, UK，其中包含正确的城市利兹。我可以从 getAddressLine(0) 中删除街道名称、邮政编码和门牌号，以保留城市。不幸的是，在某些边缘情况下，这不起作用，因为有时街道名称在 getAddressLine(0) 中包含缩写，但在 thoroughfare 中不包含缩写。

这个问题How to Get City Name by Latitude &Longitude in android?答案完全不同，因为不同国家的地址存储方式不同。

为了获取英国两个邻近城市的城市名称，我需要编写相当多的变化和边缘情况。如何从世界各地的任何纬度或经度获得正确的城市名称？世界上有太多的城市需要测试我的代码和编码，并且可能存在许多我不知道的边缘情况和变化。

编辑

下面的函数可以正确获取英国的城市。不幸的是，它在美国和印度以及可能在任何有州的国家都失败了。

private fun getCity(context: Context, latitude: Float, longitude: Float): String {
    val gcd = Geocoder(context, Locale.getDefault())
    val addresses = gcd.getFromLocation(latitude.toDouble(), longitude.toDouble(), 1)
    if (addresses.size > 0) {
        val locality = addresses[0].locality
        val getAddressLine0 = addresses[0].getAddressLine(0)
        if (getAddressLine0 != null) {
            val strs = getAddressLine0.split(",").toTypedArray()
            if (strs.count() == 1) {
                if (locality != null && locality != "") {
                    return "$locality, ${strs[0]}"
                }
                return strs[0]
            }
            for (str in strs) {
                var tempStr = str.replace(postalCode, "")
                if (tempStr != str) {
                    tempStr = tempStr.trim()
                    if (locality != null && locality != "" && locality != tempStr) {
                        return "$locality, $tempStr"
                    }
                    return tempStr
                }
            }
        }
        if (locality != null) {
            return locality
        }
    }
    return ""
}

Answer 1

Geocoder geocoder = new Geocoder(this, Locale.getDefault());
List addresses = geocoder.getFromLocation(MyLat, MyLong, 1); 
String cityName = addresses.get(0).getAddressLine(0); 
String stateName = addresses.get(0).getAddressLine(1); 
String countryName = addresses.get(0).getAddressLine(2);