Java - 复数矩阵

Question

我想创建一个类 ComplexMatrix，其字段为 ComplexNumber 类型的数组 [NxN]。我已经创建了一个 ComplexNumber 类，如下所示:

public class ComplexNumber {

    private double real;
    private double img;

    // Getters and setters
    public double getReal() {
        return real;
    }

    public void setReal(double real) {
        this.real = real;
    }

    public double getImg() {
        return img;
    }

    public void setImg(double img) {
        this.img = img;
    }

    // Constructor
    public ComplexNumber(double real, double img) {
        this.real = real;
        this.img = img;
    }

    // Add
    public ComplexNumber addComp(ComplexNumber num) {

        ComplexNumber num1 = new ComplexNumber(real + num.real, img + num.img);

        return num1;
    }

    // Subtract
    public ComplexNumber subtractComp(ComplexNumber num) {

        ComplexNumber num1 = new ComplexNumber(real - num.real, img - num.img);

        return num1;
    }

    // Multiply
    public ComplexNumber multiplyComp(ComplexNumber num) {

        ComplexNumber num1 = new ComplexNumber(real*num.real-img*num.img,real*num.img+img*num.real);

        return num1;
    }

    // Is Equals
    boolean equals(ComplexNumber num) {

        ComplexNumber num1 = new ComplexNumber(real, img);
        if (num.real == num1.real && num.img == num1.img) {
            return true;
        } else {
            return false;
        }

    }

    @Override
    public String toString() {

        if (img > 0) {
            return getReal() + " + " + Math.abs(getImg()) + "i";
        }
        if (img < 0) {
            return getReal() + " - " + Math.abs(getImg()) + "i";
        }
        if (real==0) {
            return getImg() + "i";
        }
        if (img==0) {
            return getReal() + "";
        }
        return null;
    }

}

它有一些方法和它自己的 toString，打印如下:

  3.51 + 1.87i
    2.35 - 5.61i
    -8.45 + 2.65i

实现的 ComplexMatrix 有一个数组 [M][N] 作为字段，并且 cronstructor public ComplexMatrix(int rows, int cols) 给出该数组使用方法computeRandom从一到十随机数。然后一个toString() 函数(也实现了 ComplexNumber 类中的 toSting())，应该打印随机数数组。所需的 ComplexMatrix 打印结果为:

[1.24 + 2.55i, -0.32 + 2.00i, 1.35 - 5.88i;
-5.71 - 5.91i, 0.29 – 9.14i, 0.00 + 3.51i;
6.44 + 0.00i, -3.51 – 0.67i, 2.10 + 4.20i;]

这是 ComplexMatrix 类:

         import java.util.Random;

public class ComplexMatrix {

    private ComplexNumber[][] complexArray;

    // Default Constructor
    public ComplexMatrix() {
        super();
        this.complexArray = null;
    }

    // Copy Constructor
    public ComplexMatrix(ComplexMatrix original) {
        super();
        original.complexArray = complexArray;
    }

    private Random rand = new Random();

    private double computeRandom() {
        int randomNum = (int) ((rand.nextDouble() - 0.5) * rand.nextInt(20) * 100);
        return randomNum / 100.0;
    }

    // Random Numbers Constructor
    public ComplexMatrix(int rows, int cols)  {

        double real = 0;
        double img = 0;

        ComplexNumber[][] complexArray= new ComplexNumber[rows][cols];

        for (int i = 0; i < rows; i++) {
            System.out.print("\n");
            for (int j = 0; j < cols; j++) {
                real = computeRandom();
                img = computeRandom();
                complexArray[i][j] = new ComplexNumber(real, img);
                //edw peiramatizomai..to print 8a ginetai sthn toString()
                System.out.print(complexArray[i][j].toString());
                System.out.print("\t");
            }
        }

    }

    @Override
    public String toString() {
        int rows = 0,cols = 0;
        //ComplexNumber[][] complexArray= new ComplexNumber[rows][cols];
        ComplexMatrix s = new ComplexMatrix(rows,cols);

        String out = "[";
        //????????????????????????????????????
        for (int i = 0; i < rows; i++)
            for (int j = 0; j < cols; j++) {
                //????????
                out = s.toString();

            }
        out += "]";
        return out;

    }
}

Answer 1

我将给出伪代码(部分假设这是一个作业)。但希望这足以让您开始实现，而无需简单地给出解决方案。

@Override
public String toString() {
    out = "[";
    for (row : rows) {
        if (notFirstRow) {
            out += "\n"; // New line
        }
        for (column : columns) {
            if (notFirstColumn) {
                out += ", ";
            }
            out += matrix[row][column].toString();
        }
    }
    out += "]";
    return out;
}

警告，我没有声称这是最佳的，或者没有更好的方法来格式化矩阵(或复数)......但是如果你能充实它以实际编译，我怀疑你会得到你想要的东西。