python - 如何在python中对字典索引进行排序

Question

我有一种方法可以从 1 开始递增的索引中对团队值进行排序。它看起来像这样:

def create_ranking():
    sort_one = sorted(team_scores.items(), key=itemgetter(0))
    teams_sorted = sorted(sort_one, key=itemgetter(1), reverse=True)
    for idx, (team, score) in enumerate(teams_sorted, 1):
        suffix = 'pt' if score ==1 else 'pts'
        print(f'{idx}. {team + ","} {score} {suffix}')

它目前给我这个输出:

1. Tarantulas, 6 pts
2. Lions, 5 pts
3. FC Awesome, 1 pt
4. Snakes, 1 pt
5. Grouches, 0 pts

目前是根据分值对字典进行排序，如果分值相同，则按字母顺序排序。

如果我需要显示在相同索引值上具有相同分数的团队，我该如何对字典进行排序。例如:

1. Tarantulas, 6 pts
2. Lions, 5 pts
*3. FC Awesome, 1 pt
3. Snakes, 1 pt*
4. Grouches, 0 pts

Answer 1

使用 itertools.groupby 将得分相同的团队聚集在一起，然后遍历每个组:

from operator import itemgetter
import itertools

sort_one = [
    ('Tarantulas', 6),
    ('Lions', 5),
    ('FC Awesome', 1),
    ('Snakes', 1),
    ('Grouches', 0),
]
teams_sorted = sorted(sort_one, key=itemgetter(1), reverse=True)
for idx, (score, group) in enumerate(itertools.groupby(teams_sorted, itemgetter(1)), 1):
    for team, ignore_score  in group:
        suffix = 'pt' if score ==1 else 'pts'
        print('{idx}. {team}, {score} {suffix}'.format(idx=idx, team=team, score=score, suffix=suffix))