python - 在 python 中读取 json 值时出现无效参数错误

Question

在 python 中读取外部 json 文件的值时出现无效参数错误

我试过:

import json

with open('https://www.w3schools.com/js/json_demo.txt') as json_file:
    data = json.load(json_file)
    #for p in data['people']:
    print('Name: ' + data['name'])

给我错误:

with open('https://www.w3schools.com/js/json_demo.txt') as json_file: OSError: [Errno 22] Invalid argument: 'https://www.w3schools.com/js/json_demo.txt'

Answer 1

因为 open 用于打开本地文件，而不是 jonrsharpe 评论的 URL所以，选择urllib正如 fl00r 评论的那样.

虽然他提供的链接是python-2

试试这个(python-3):

import json
from urllib.request import urlopen

with urlopen('https://www.w3schools.com/js/json_demo.txt') as json_file:
    data = json.load(json_file)
    #for p in data['people']:
    print('Name: ' + data['name'])

John