python - 制作缩写 - 选择非停用词的第一个字符

Question

给定一个停用词列表和一个数据框，其中 1 列具有完整形式，如图所示 -

stopwords = ['of', 'and', '&', 'com', 'org']
df = pd.DataFrame({'Full form': ['World health organization', 'Intellectual property', 'royal bank of canada']})
df

+---+---------------------------+
|   |         Full form         |
+---+---------------------------+
| 0 | World health organization |
| 1 | Intellectual property     |
| 2 | Royal bank of canada      |
+---+---------------------------+

我正在寻找一种方法来使相邻的列的缩写忽略停用词(如果有的话)。

预期输出:

+---+---------------------------+----------------+
|   |         Full form         |   Abbreviation |
+---+---------------------------+----------------+
| 0 | World health organization |   WHO          |
| 1 | Intellectual property     |   IP           |
| 2 | Royal bank of canada      |   RBC          |
+---+---------------------------+----------------+

Answer 1

应该这样做:

import pandas as pd

stopwords = ['of', 'and', '&', 'com', 'org']
df = pd.DataFrame({'Full form': ['World health organization', 'Intellectual property', 'royal bank of canada']})


def abbrev(t, stopwords=stopwords):
    return ''.join(u[0] for u in t.split() if u not in stopwords).upper()


df['Abbreviation'] = df['Full form'].apply(abbrev)

print(df)

输出

                   Full form Abbreviation
0  World health organization          WHO
1      Intellectual property           IP
2       royal bank of canada          RBC