python - 比较列表元素与多个列表元素

Question

我有两个列表:

targets = [ [ [4.88], [2.76], [0.4] ], [ [2.6], [2.12], [7.4], [0.2] ] ]
multiples = [ [ [4.2, 3.6, 6.3], [3.5, 2.5], [7.3, 0.5] ], [ [3.6, 0.3], [5.2, 8.6, 3.7], [3.6, 0.4], [2.3, 6.4] ] ]

对于第一个列表中的每个条目，第二个列表中有多个条目。现在我想比较这些数字并计算低于目标数字的数字的准确度。我尝试了以下方法，但我不知道如何将一个值与多个值进行比较以及如何同时引用它们。

for element in targets:
    tmp = []
    for item in element:
        tmp2 = []
        if item > multiples

输出应该是这样的:

[ [ [2], [1], [0] ], [ [1], [0], [2], [0] ] ]

有人知道解决方案吗？

Answer 1

一个使用zip() 和sum() 的解决方案:

targets = [ [ [4.88], [2.76], [0.4] ], [ [2.6], [2.12], [7.4], [0.2] ] ]
multiples = [ [ [4.2, 3.6, 6.3], [3.5, 2.5], [7.3, 0.5] ], [ [3.6, 0.3], [5.2, 8.6, 3.7], [3.6, 0.4], [2.3, 6.4] ] ]

out = []
for val1, val2 in zip(targets, multiples):
    out.append([[sum(i < j for i in vval2) for j in vval1] for (vval1, vval2) in zip(val1, val2)])

print(out)

打印:

[[[2], [1], [0]], [[1], [0], [2], [0]]]