Python/函数参数

Question

主要目标:从文本文件中读取最高分的功能。要传递给函数的参数:一个文本文档!

def highscore():
    try:
        text_file = open ("topscore.txt", "r")
        topscore = int(text_file.read())
        print topscore
        text_file.close()
        return topscore
    except:
        print "Error - no file"
        topscore = 0
        return topscore

如何添加文本文件作为参数？

Answer 1

def highscore(filename):
    try:
        text_file = open (filename, "r")

哦，你应该停止在 try block 中放入不必要的代码。干净的解决方案如下所示:

def highscore(filename):
    if not os.path.isfile(filename):
        return 0
    with open(filename, 'r') as f:
        return int(f.read())

或者，如果您希望在任何读取文件失败的情况下返回 0:

def highscore(filename):
    try:
        with open(filename, 'r') as f:
            return int(f.read())
    except:
        return 0