java - 掩码 - 带星号的地址(星号) - 如果数组长度为 1？

Question

对于这种情况，我有一个数组超出范围。

1. 如果我这样做:

   字符串地址 =“100 Point St Apt B”

   它也应该被屏蔽:100 Po*** St Apt *

2. 如果我这样做:

   字符串地址 =“100 Point St Apt 132”

   它也被屏蔽了:100 Po*** St Apt ***

有人可以告诉我我在这里做错了什么吗？谢谢!!

public String mask(String address) {
        String[] splitAddress = address.split(" ");
        StringBuilder stringBuilder = new StringBuilder();
        String maskedAddress = "";

    String streetNum = splitAddress[0];
    stringBuilder.append(streetNum + " ");



    for (int i = 1; i < splitAddress.length; i++) {
                String splitFirstTwoCharacters = splitAddress[i].substring(0, 2);
                String remainingCharactersOfAddress = splitAddress[i].substring(2);
                String maskAddress = remainingCharactersOfAddress.replaceAll(".", "*");
                maskedAddress = stringBuilder.append(splitFirstTwoCharacters).append(maskAddress + " ").toString().trim();
    }
 return maskedAddress;
}

Answer 1

当您执行 splitAddress[i].substring(0, 2) 时，splitAddress 部分之一是 B，它的 endIndex 不为 2。因此它是越界的。