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java - 当收到 NumberFormatException 时,如何阻止或重做 SWING 输入?

转载 作者:太空宇宙 更新时间:2023-11-04 09:12:48 25 4
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我正在制作一个彩票程序,它从用户处获取 3 个独立的整数输入,并将其与 3 个随机的一位数输入进行比较(我使用了 2 个数组,一个用于随机,另一个用于用户输入)。我已经设法检查输入的长度是否超过一位数字,但当我的程序收到字符串或字符输入时,我不知道如何进行检查。

第 31-42 行是检查用户输入的代码块

import javax.swing.*;

public class Lottery_Swing {
public static void main(String[] args) {

final int HIGHEST_VALUE = 10;
final int LOWEST_VALUE = 0;
final int LIMIT = 3;

int[] array1 = new int[LIMIT];
int[] array2 = new int[LIMIT];
int[] array3 = new int[LIMIT];

int randomValue;
int numberInput;
int numberMatched = 0;

boolean exactOrder = true;

//taking 3 random numbers and storing into array1//
for(int counter = 0; counter < LIMIT; counter++) {
randomValue = ((int)(Math.random() * 100) % HIGHEST_VALUE + LOWEST_VALUE);
array1[counter] = randomValue;
}

for(int counter = 0; counter < LIMIT; counter++) {
array3[counter] = array1[counter];
}

//Taking 3 numbers from user and storing into array2//
JOptionPane.showMessageDialog(null,"Enter 3 one-digit positive numbers for your 3 guesses");
for(int counter = 0; counter < LIMIT; counter++) {
String num1= JOptionPane.showInputDialog("Please input Guess #" + (counter+1));
numberInput = Integer.parseInt(num1);
if(numberInput < 0 || numberInput > 9) {
JOptionPane.showMessageDialog(null,"Please input a ONE-DIGIT POSITIVE Number for:");
JOptionPane.showMessageDialog(null,"Guess #" + (counter+1));
num1= JOptionPane.showInputDialog("Please input Guess #" + counter);
numberInput = Integer.parseInt(num1);
}
array2[counter] = numberInput;
}

//Checks for how many numbers matched//
for (int counter = 0; counter < LIMIT; counter++) {
for (int counter2 = 0; counter2 < LIMIT; counter2++) {

if(array2[counter] == array3[counter2]) {
numberMatched++;
array3[counter2] = 99;
break;
}
}
}
//If 3 numbers matched, it checks if it is in order//
if(numberMatched == 3) {
for (int counter = 0; counter < LIMIT; counter++) {
if(array2[counter] == array1[counter]) {

}
else {
exactOrder = false;
continue;
}
}
}

//Result Checking//
if(numberMatched == 3 && exactOrder == true) {
JOptionPane.showMessageDialog(null,"You won 1000000. All numbers match, and are in order.");
}
else {
if(numberMatched == 3) {
JOptionPane.showMessageDialog(null,"You won 1000. All Numbers match.");
}
else {
if(numberMatched == 2) {
JOptionPane.showMessageDialog(null,"You won 100. 2 Numbers match.");
}
else {
if(numberMatched == 1) {
JOptionPane.showMessageDialog(null,"You won 10. 1 Number matched.");
}
else {
JOptionPane.showMessageDialog(null,"No Matches");
}
}
}
}
//Result Display//
JOptionPane.showMessageDialog(null,"The winning numbers were:" + "\n" + array1[0] + " " + array1[1] + " " + array1[2] + "\n You entered:" + "\n" + array2[0] + " " + array2[1] + " " + array2[2] );
}
}

最佳答案

我建议以下基于递归 checkNum 方法的解决方案,该方法使用简单的正则表达式和值检查来完成所有验证:

import javax.swing.*;

public class Lottery_Swing {

public static void main(String[] args) {

final int HIGHEST_VALUE = 10;
final int LOWEST_VALUE = 0;
final int LIMIT = 3;

int[] array1 = new int[LIMIT];
int[] array2 = new int[LIMIT];
int[] array3 = new int[LIMIT];

int randomValue;
int numberInput;
int numberMatched = 0;

boolean exactOrder = true;

//taking 3 random numbers and storing into array1//
for (int counter = 0; counter < LIMIT; counter++) {
randomValue = ((int) (Math.random() * 100) % HIGHEST_VALUE + LOWEST_VALUE);
array1[counter] = randomValue;
}

for (int counter = 0; counter < LIMIT; counter++) {
array3[counter] = array1[counter];
}

//Taking 3 numbers from user and storing into array2//
JOptionPane.showMessageDialog(null, "Enter 3 one-digit positive numbers for your 3 guesses");
for (int counter = 0; counter < LIMIT; counter++) {
String num1 = JOptionPane.showInputDialog("Please input Guess #" + (counter + 1));
num1 = checkNum(num1, (counter + 1));
numberInput = Integer.parseInt(num1);
array2[counter] = numberInput;
}

//Checks for how many numbers matched//
for (int counter = 0; counter < LIMIT; counter++) {
for (int counter2 = 0; counter2 < LIMIT; counter2++) {

if (array2[counter] == array3[counter2]) {
numberMatched++;
array3[counter2] = 99;
break;
}
}
}
//If 3 numbers matched, it checks if it is in order//
if (numberMatched == 3) {
for (int counter = 0; counter < LIMIT; counter++) {
if (array2[counter] == array1[counter]) {

} else {
exactOrder = false;
continue;
}
}
}

//Result Checking//
if (numberMatched == 3 && exactOrder == true) {
JOptionPane.showMessageDialog(null, "You won 1000000. All numbers match, and are in order.");
} else {
if (numberMatched == 3) {
JOptionPane.showMessageDialog(null, "You won 1000. All Numbers match.");
} else {
if (numberMatched == 2) {
JOptionPane.showMessageDialog(null, "You won 100. 2 Numbers match.");
} else {
if (numberMatched == 1) {
JOptionPane.showMessageDialog(null, "You won 10. 1 Number matched.");
} else {
JOptionPane.showMessageDialog(null, "No Matches");
}
}
}
}
//Result Display//
JOptionPane.showMessageDialog(null, "The winning numbers were:" + "\n" + array1[0] + " " + array1[1] + " " + array1[2] + "\n You entered:" + "\n" + array2[0] + " " + array2[1] + " " + array2[2]);
}

public static String checkNum(String num1, int n) {
String res = num1;
if (!num1.matches("\\d+")) {
res = JOptionPane.showInputDialog("You entered an invalid integer. Please input a correct positive value for Guess #" + n);
res = checkNum(res, n);
}
int v = Integer.parseInt(res);
if (v < 0 || v > 9) {
res = JOptionPane.showInputDialog("Please input a ONE-DIGIT POSITIVE Number for Guess #" + n);
res = checkNum(res, n);
}

return res;
}
}

请注意,您使用 numberInput 进行的检查已替换为 checkNum 调用。

关于java - 当收到 NumberFormatException 时,如何阻止或重做 SWING 输入?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/59478171/

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