python - 如何将列表拆分为 N 个随机但最小大小的 block

Question

例如:我想将range(37)分成n=5 block ，每个 block 有
长度( block )>= 4。

Answer 1

>>> def divide(lst, min_size, split_size):
    it = iter(lst)
    from itertools import islice
    size = len(lst)
    for i in range(split_size - 1,0,-1):
        s = random.randint(min_size, size -  min_size * i)
        yield list(islice(it,0,s))
        size -= s
    yield list(it)


>>> list(divide(range(37), 4, 5))
[[0, 1, 2, 3], [4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22], [23, 24, 25, 26, 27], [28, 29, 30, 31], [32, 33, 34, 35, 36]]
>>> list(divide(range(37), 4, 5))
[[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16], [17, 18, 19, 20, 21, 22], [23, 24, 25, 26], [27, 28, 29, 30, 31], [32, 33, 34, 35, 36]]
>>> list(divide(range(37), 4, 5))
[[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11], [12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23], [24, 25, 26, 27, 28], [29, 30, 31, 32], [33, 34, 35, 36]]
>>> list(divide(range(37), 4, 5))
[[0, 1, 2, 3, 4, 5, 6], [7, 8, 9, 10, 11, 12, 13, 14, 15, 16], [17, 18, 19, 20, 21, 22, 23, 24], [25, 26, 27, 28, 29, 30, 31], [32, 33, 34, 35, 36]]
>>>