python - 索引 JSON 搜索 python

Question

我有下一个从 URL 获得的 JSON:

[{
  "id": 1,
  "version": 23,
  "external_id": "2312",
  "url": "https://example.com/432",
  "type": "typeA",
  "date": "2",
  "notes": "notes",
  "title": "title",
  "abstract": "dsadasdas",
  "details": "something",
  "accuracy": 0,
  "reliability": 0,
  "severity": 12,
  "thing": "32132",
  "other": [
    "aaaaaaaaaaaaaaaaaa",
    "bbbbbbbbbbbbbb",
    "cccccccccccccccc",
    "dddddddddddddd",
    "eeeeeeeeee"
  ],
  "nana": 8
},
{
  "id": 2,
  "version": 23,
  "external_id": "2312",
  "url": "https://example.com/432",
  "type": "typeA",
  "date": "2",
  "notes": "notes",
  "title": "title",
  "abstract": "dsadasdas",
  "details": "something",
  "accuracy": 0,
  "reliability": 0,
  "severity": 12,
  "thing": "32132",
  "other": [
    "aaaaaaaaaaaaaaaaaa",
    "bbbbbbbbbbbbbb",
    "cccccccccccccccc",
    "dddddddddddddd",
    "eeeeeeeeee"
  ],
  "nana": 8
}]

我的代码:

import json
import urllib2

data = json.load(urllib2.urlopen('http://someurl/path/to/json'))
print data

例如，我想知道如何访问“id”等于 2 的对象的“抽象”部分。 “id”部分是唯一的，所以我可以使用 id 来索引我的搜索。

谢谢!

Answer 1

这是一种方法。您可以通过生成器表达式创建一个生成器，调用 next 来迭代该生成器一次，然后取回所需的对象。

item = next((item for item in data if item['id'] == 2), None)
if item:
    print item['abstract']

另见 Python: get a dict from a list based on something inside the dict

编辑:如果您想访问列表中具有给定键值的所有元素(例如，id == 2) 你可以做两件事之一。您可以通过理解创建列表(如其他答案所示)，也可以更改我的解决方案:

my_gen = (item for item in data if item['id'] == 2)
for item in my_gen:
    print item

在循环中，item 将遍历列表中满足给定条件(此处为 id == 2)的项目。