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java - Jackson JSON 处理器 : SerializationConfig. Feature.USE_ANNOTATIONS 设置为 false

转载 作者:太空宇宙 更新时间:2023-11-04 09:06:21 31 4
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您好,我在将 Jackson JSON 处理器与 ObjectMapper 类一起使用时遇到了一个棘手的问题。这是我的测试类,应该将对象 (UserHeader) 序列化为 Json 字符串。

 import org.codehaus.jackson.map.ObjectMapper;
import org.codehaus.jackson.map.SerializationConfig;

public class TestJson {

public static void main(String[] args) throws Exception {
ObjectMapper mapper = new ObjectMapper();
UserHeader userHeader = new UserHeader();
userHeader.setFirstName("A");
userHeader.setLastName("A1");
userHeader.setSystem("2A");

mapper.configure(SerializationConfig.Feature.USE_ANNOTATIONS, false);
StringWriter sw = new StringWriter();
mapper.writeValue(sw, userHeader);
System.out.println(sw.toString());
}
}

这是我的 UserHeader 类,带有从不同的 ObjectMapper(不是这个)使用的注释

  import org.codehaus.jackson.annotate.JsonIgnore;
import org.codehaus.jackson.annotate.JsonProperty;
import org.codehaus.jackson.map.annotate.JsonSerialize;
import org.codehaus.jackson.map.annotate.JsonSerialize.Typing;

@JsonSerialize(typing=Typing.STATIC)
public class UserHeader implements Serializable,LoggedObject, MessagesInterface {

private static final long serialVersionUID = 1L;

private String system;
private String userName;
private String firstName;
private String lastName;

private List<Scrivania> scrivanie;

public String getUserName() {
return userName;
}

public void setUserName(String userName) {
this.userName = userName;
}

@JsonProperty("Nome utente")
public String getFirstName() {
return firstName;
}

public void setFirstName(String firstName) {
this.firstName = firstName;
}

@JsonProperty("Cognome utente")
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}

@JsonProperty("Scrivanie associate")
public List<Scrivania> getScrivanie() {
return scrivanie;
}
public void setScrivanie(List<Scrivania> scrivanie) {
this.scrivanie = scrivanie;
}
@JsonProperty("Sistema (IAM o EDOC)")
public String getSystem() {
return system;
}
public void setSystem(String system) {
this.system = system;
}

@Override
@JsonIgnore
public String getObjectId() {
return this.userName;
}

@Override
@JsonIgnore
public Object getObjectData() {
try {
return this.clone();
}
catch (Exception e) {
return null;
}
}
@Override
public String getName() {
return this.userName;
}
}

但是,如果我运行 main 方法,系统会返回给我这个异常:

Exception in thread "main" java.lang.NullPointerException
at org.codehaus.jackson.map.introspect.AnnotatedClass.resolveClassAnnotations(AnnotatedClass.java:295)
at org.codehaus.jackson.map.introspect.AnnotatedClass.construct(AnnotatedClass.java:141)
at org.codehaus.jackson.map.introspect.BasicClassIntrospector.forClassAnnotations(BasicClassIntrospector.java:185)
at org.codehaus.jackson.map.introspect.BasicClassIntrospector.forClassAnnotations(BasicClassIntrospector.java:15)
at org.codehaus.jackson.map.SerializationConfig.introspectClassAnnotations(SerializationConfig.java:661)
at org.codehaus.jackson.map.ser.BasicSerializerFactory.createTypeSerializer(BasicSerializerFactory.java:180)
at org.codehaus.jackson.map.ser.BeanSerializerFactory.findPropertyContentTypeSerializer(BeanSerializerFactory.java:406)
at org.codehaus.jackson.map.ser.BeanSerializerFactory._constructWriter(BeanSerializerFactory.java:778)
at org.codehaus.jackson.map.ser.BeanSerializerFactory.findBeanProperties(BeanSerializerFactory.java:608)
at org.codehaus.jackson.map.ser.BeanSerializerFactory.constructBeanSerializer(BeanSerializerFactory.java:436)
at org.codehaus.jackson.map.ser.BeanSerializerFactory.findBeanSerializer(BeanSerializerFactory.java:349)
at org.codehaus.jackson.map.ser.BeanSerializerFactory.createSerializer(BeanSerializerFactory.java:295)
at org.codehaus.jackson.map.ser.StdSerializerProvider._createUntypedSerializer(StdSerializerProvider.java:778)
at org.codehaus.jackson.map.ser.StdSerializerProvider._createAndCacheUntypedSerializer(StdSerializerProvider.java:731)
at org.codehaus.jackson.map.ser.StdSerializerProvider.findValueSerializer(StdSerializerProvider.java:369)
at http://stackoverflow.com/questions/6661717/how-to-process-an-invalid-value-with-jackson-json-processororg.codehaus.jackson.map.ser.StdSerializerProvider.findTypedValueSerializer(StdSerializerProvider.java:452)
at org.codehaus.jackson.map.ser.StdSerializerProvider._serializeValue(StdSerializerProvider.java:597)
at org.codehaus.jackson.map.ser.StdSerializerProvider.serializeValue(StdSerializerProvider.java:280)
at org.codehaus.jackson.map.ObjectMapper._configAndWriteValue(ObjectMapper.java:2260)
at org.codehaus.jackson.map.ObjectMapper.writeValue(ObjectMapper.java:1813)
at it.unina.edoc.json.TestJson.main(TestJson.java:65)

我不知道这个异常,因为由于 USE_ANNOTATION false 配置,@Annotations 应该被忽略。此外,如果我将 USE_ANNOTATION 设置为 true,错误就会消失。我的构建路径上有这些 jar :

  • jackson-core-asl-1.8.3.jar
  • jackson-jaxrs-1.8.3.jar
  • jackson-mapper-asl-1.8.3.jar
  • jackson-xc-1.8.3.jar

最佳答案

使用 DeserializationConfig.Feature.USE_ANNOTATIONS 属性(设置为 false)将导致 JACKSON DeserializerConfig 类使用 NopAnnotationIntrospector。然后将使用此 NopAnnotationIntrospector 解析类的注释。 NopAnnotationIntrospector 将在每个 isHandled 请求上为类上的任何注释返回 false - 实际上不会在进一步处理中使用此注释。

所以 - 系统仍然“检查”注释 - 在这种情况下必须在类路径上。由于 Android 不提供任何 jaxb-api 注释,这会导致 NoClassDefFoundError。

我预计 USE_ANNOTATIONS = false 会让 JACKSON 完全忽略任何注释 - 但不幸的是它没有。我现在将使用 Jackson Streaming API 来解析 JSON 字符串,而不是使用 JACKSON 数据绑定(bind)功能。

关于java - Jackson JSON 处理器 : SerializationConfig. Feature.USE_ANNOTATIONS 设置为 false,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/10418352/

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