java - java中如何删除数组中的索引

Question

我想从数组中删除给定的索引，并在删除索引后更新数组。数组大小必须与之前的相同。

任务就是这个

import java.util.*;
class Example{
    public static void main(String args[]){
        int[] xr={0,10,20,30,40,50,60,70,80,90};
        System.out.println(Arrays.toString(xr));//[0,10,20,30,40,50,60,70,80,90]
        delete(2, xr); //delete(int index, int[] array)
        System.out.println(Arrays.toString(xr));//[0,10,30,40,50,60,70,80,90,0]

        delete(2, xr); //delete(int index, int[] array)
        System.out.println(Arrays.toString(xr));//[0,10,40,50,60,70,80,90,0,0]

        delete(3, xr); //delete(int index, int[] array)
        System.out.println(Arrays.toString(xr));//[0,10,40,60,70,80,90,0,0,0]
    }
}

我尝试了这种方式。但我不确定这个是否正确。

import java.util.*;
class Example{
    public static void main(String args[]){
        int[] xr={0,10,20,30,40,50,60,70,80,90};
        System.out.println(Arrays.toString(xr));//[0,10,20,30,40,50,60,70,80,90]
        delete(2, xr); //delete(int index, int[] array)
        System.out.println(Arrays.toString(xr));//[0,10,30,40,50,60,70,80,90,0]

        delete(2, xr); //delete(int index, int[] array)
        System.out.println(Arrays.toString(xr));//[0,10,40,50,60,70,80,90,0,0]

        delete(3, xr); //delete(int index, int[] array)
        System.out.println(Arrays.toString(xr));//[0,10,40,60,70,80,90,0,0,0]
    }

    public static void delete(int index,int[] array)
    {
        for (int i = 0; i <array.length ; i++)
        {
            if (i==index)
            {
                array[i]=array[i+1];
            }
            if (i>index && i<array.length-1)
            {
                array[i]=array[i+1];
            }

        }   
        array[array.length-1]=0;    
    }
}

Answer 1

public static void delete(int index,int[] array){
        if(index < 0 || index > array.length){
            return; // or throw error
        }

        for(int cpt = index; cpt < array.length - 1 ; cpt++){
            array[cpt] = array[cpt+1];
        }

        array[array.length - 1] = 0;
    }

它有效，我希望这就是你想要的