linux - 如何在一行中搜索模式并打印该行中该模式之后存在的数据

Question

我有如下不均匀线条的文件:

jacktyutu/ABC/uyiyi/yyuiyiu/1.java
adhjasgdhg/gsdjgf/ABC/sdfhgsdfj/sdjfhsd/sdfkjhsdkf/2.java
adhjasgdhg/01/ABC/sdfhgs/213/j/sdjfhsd/sdfkjhsdkf/3.java
sd/asd/asd/ABC/sdjg/76/987/4.java

从上面的文件中，我想从每一行中搜索模式 ABC 并打印该行中的其余数据以用于 ex

我的输出应该如下:

uyiyi/yyuiyiu/1.java
sdfhgsdfj/sdjfhsd/sdfkjhsdkf/2.java
sdfhgs/213/j/sdjfhsd/sdfkjhsdkf/3.java
sdjg/76/987/4.java

如何在 shell 脚本中或使用 awk 和 sed 实现这一点？

Answer 1

使用GNU Grep:

$ grep -oP "(?<=ABC/).*" file
uyiyi/yyuiyiu/1.java
sdfhgsdfj/sdjfhsd/sdfkjhsdkf/2.java
sdfhgs/213/j/sdjfhsd/sdfkjhsdkf/3.java
sdjg/76/987/4.java

使用awk:

$ awk -F'ABC/' '{print $2}' file
uyiyi/yyuiyiu/1.java
sdfhgsdfj/sdjfhsd/sdfkjhsdkf/2.java
sdfhgs/213/j/sdjfhsd/sdfkjhsdkf/3.java
sdjg/76/987/4.java

使用sed:

$ sed 's%.*ABC/%%' file
uyiyi/yyuiyiu/1.java
sdfhgsdfj/sdjfhsd/sdfkjhsdkf/2.java
sdfhgs/213/j/sdjfhsd/sdfkjhsdkf/3.java
sdjg/76/987/4.java