Python SSH 命令

Question

我有以下代码:

def executeRemoteCommand(host, command):
    cmd = "ssh " + host + " \'" + command + "\'"
    print cmd
    subprocess.check_call(cmd)

当我运行命令时:

java -Xss515m -Xms48g -Xmx48g -XX:+UseConcMarkSweepGC -XX:+PrintGCDetails -XX:+PrintGCTimeStamps -jar /local/experiments/helloworld/ro/server.jar /local/experiments/helloworld/ro/properties.json

使用上面的函数，我得到以下错误

File "./util/ssh_util.py", line 85, in executeRemoteCommand
    subprocess.check_call(cmd)
  File "/usr/lib/python2.7/subprocess.py", line 506, in check_call
    retcode = call(*popenargs, **kwargs)
  File "/usr/lib/python2.7/subprocess.py", line 493, in call
    return Popen(*popenargs, **kwargs).wait()
  File "/usr/lib/python2.7/subprocess.py", line 679, in __init__
    errread, errwrite)
  File "/usr/lib/python2.7/subprocess.py", line 1259, in _execute_child
    raise child_exception
OSError: [Errno 2] No such file or directory.

但是，当我直接在命令行中输入调用时，它工作正常。

ssh foo92 'java -Xss515m -Xms48g -Xmx48g -XX:+UseConcMarkSweepGC -XX:+PrintGCDetails -XX:+PrintGCTimeStamps -jar /local/experiments/helloworld/ro/server.jar /local/experiments/helloworld/ro/properties.json'

有人知道吗？

Answer 1

您需要设置 shell=True 以通过 shell 执行该命令:

subprocess.check_call(cmd, shell=True)

如果您将参数作为列表传递，您可以直接执行它，而不是通过 shell 推送它；这样你就不必担心引用命令:

def executeRemoteCommand(host, command):
    subprocess.check_call(['ssh', host, command])

请注意，此处的 host 和 command 都是传递给 ssh 的单个参数。通常，这就是 shell 将参数传递给 ssh 命令的方式，这就是 java ... 命令行周围的引号 for.