python - Unicode 警告 : Unicode equal comparison failed to convert both arguments to Unicode

Question

我知道很多人以前遇到过这个错误，但我找不到解决问题的办法。

我有一个要规范化的 URL:

url = u"http://www.dgzfp.de/Dienste/Fachbeitr%C3%A4ge.aspx?EntryId=267&Page=5"
scheme, host_port, path, query, fragment = urlsplit(url)
path = urllib.unquote(path)
path = urllib.quote(path,safe="%/")

这给出了一条错误信息:

/usr/lib64/python2.6/urllib.py:1236: UnicodeWarning: Unicode equal comparison failed to convert both arguments to Unicode - interpreting them as being unequal
  res = map(safe_map.__getitem__, s)
Traceback (most recent call last):
  File "url_normalization.py", line 246, in <module>
    logging.info(get_canonical_url(url))
  File "url_normalization.py", line 102, in get_canonical_url
    path = urllib.quote(path,safe="%/")
  File "/usr/lib64/python2.6/urllib.py", line 1236, in quote
    res = map(safe_map.__getitem__, s)
KeyError: u'\xc3'

我试图从 URL 字符串中删除 unicode 指示符“u”，但我没有收到错误消息。但是我怎样才能自动摆脱 unicode 因为我直接从数据库中读取它。

Answer 1

urllib.quote() 没有正确解析 Unicode。要解决这个问题，您可以在读取 url 时调用 .encode() 方法(或从数据库中读取的变量)。所以运行 url = url.encode('utf-8')。有了这个，您将获得:

import urllib
import urlparse
from urlparse import urlsplit

url = u"http://www.dgzfp.de/Dienste/Fachbeitr%C3%A4ge.aspx?EntryId=267&Page=5"
url = url.encode('utf-8')
scheme, host_port, path, query, fragment = urlsplit(url)
path = urllib.unquote(path)
path = urllib.quote(path,safe="%/")

path 变量的输出将是:

>>> path
'/Dienste/Fachbeitr%C3%A4ge.aspx'

这个有用吗？