python - 使用 python curses 逐页滚动或逐行滚动

Question

我正在尝试使用 python curses 将一些文本写入窗口。但是当我到达窗口的尽头时，我得到 addstr() returned ERR

如何逐页或逐行滚动输出。？如何绑定(bind)空格键或向下箭头？

这是我的代码:

try:
    screen = curses.initscr()
    screen.immedok(True)
    curses.start_color()
    curses.init_pair(1, curses.COLOR_GREEN, curses.COLOR_BLACK)
    curses.init_pair(2, curses.COLOR_WHITE, curses.COLOR_BLACK)
    screen.bkgd(curses.color_pair(2))
    screen.scrollok(1)
    screen.border(0)

    p = subprocess.Popen(command, stdout=subprocess.PIPE, stderr=subprocess.PIPE, shell=True)
    (output, err) = p.communicate()
    linenumber = 1
    for line in getline(output):
        if linenumber <= 2:
            # First two lines are header, mark bold
            screen.addstr(linenumber, 2, line, curses.color_pair(1)|curses.A_BOLD)
        else:
            screen.addstr(linenumber, 2, line)
        linenumber += 1

   screen.getch()
   curses.endwin()

except Exception, e:
    print "\n\033[1;91m[FAILED]\033[0m  Interrupt  ", e
    logging.error(e, exc_info=True)
    curses.endwin()

Answer 1

问题是您对 screen.addstr 的调用要求输入屏幕末尾的行号。考虑到您在屏幕上绘制的框，更好的方法是在框内创建一个新窗口(例如使用 curses.newwin)并在该窗口内编写 addstr 调用.

您的示例未按给定的方式编译。这是一个工作示例:

import curses
import logging
import subprocess
import sys

command = "ls -l /bin"
try:
    screen = curses.initscr()
    screen.immedok(True)
    curses.start_color()
    curses.init_pair(1, curses.COLOR_GREEN, curses.COLOR_BLACK)
    curses.init_pair(2, curses.COLOR_WHITE, curses.COLOR_BLACK)
    screen.bkgd(curses.color_pair(2))
    screen.border(0)
    boxed = curses.newwin(curses.LINES - 2, curses.COLS - 2, 1, 1)
    boxed.scrollok(1)

    p = subprocess.Popen(command, stdout=subprocess.PIPE, stderr=subprocess.PIPE, shell=True)
    (output, err) = p.communicate()
    linenumber = 1
    for line in output.split("\n"):
        if linenumber <= 2:
            # First two lines are header, mark bold
            boxed.addstr(line, curses.color_pair(1)|curses.A_BOLD)
        else:
            boxed.addstr(line)
        boxed.addch("\n")
        linenumber += 1
        boxed.getch()

    screen.getch()
    curses.endwin()

except Exception, e:
    print "\n\033[1;91m[FAILED]\033[0m  Interrupt  ", e
    logging.error(e, exc_info=True)