c - 如何将文字 char 十六进制值转换为十六进制值本身？

Question

我有应该存储在 unsigned char[64] 数组中的文字值。如何将此类值转换为等效的十六进制值？

int main() {

    unsigned char arry[1] = { 0xaa }

    char* str = "fe"; //I want to store 0xfe on arry[0]

    arry[0] = 0xfe; // this works, but I have to type it
    arry[0] = 0x + str; //obviously fails

    return 0;
}

有什么建议吗？

Answer 1

arr[0] = strtol(str,NULL,16);  // If one entry is big enough to hold it.