Python排列列表并将其写回文件

Question

我正在尝试制作一个脚本来查找文本文档中符号 {} 之间的所有内容。它采用 {} 中的 .txt 文档特定部分并按字母顺序对其进行组织，然后将其写回文本文档。文本文档示例..

bla bla bla 
bla ba bl bla ba bl {apple:banana, this: something else, airplane:hobby}
bla bla bla 
bla bla bla 

期望的输出(按字母顺序排序)..

bla bla bla 
bla ba bl bla ba bl {airplane:hobby, apple:banana, this: something else}
bla bla bla 
bla bla bla 

还在打印什么..

    bla bla bla 
    bla ba bl bla ba bl {apple:banana, this: something else, airplane:hobby}
    bla bla bla 
    bla bla bla 

我的代码..

def openFind():
    f = open(inFile, 'r')
    lines = f.read()
    match = re.findall(r'{(.*?)}', lines)
    before = str(match)
    n=1
    for i in xrange(0, len(match), n):
        mydict =  match[i:i+n]
        for x in sorted(mydict):
            c = x.split(',')
            newmatch = sorted(c)
            final =  str(newmatch)
            print final

            # NOT WORKING BELOW!!! Stuck in loop?
            with open(outFile,'w') as new_file:
                with open(inFile) as old_file:
                    for line in old_file:
                        new_file.write(line.replace(before, after))

它将排序/按字母顺序排列的列表打印为 [airplane:hobby, apple:banana, this: something else]，但如何用它来替换文本文档中的原始文本？必须到位，但可以创建新的 txt。

Answer 1

这应该有效:

import re

def openFind():
    with open("test.txt", "r") as in_file:
        data = in_file.read()

    def sub(m):
        l = [s.strip() for s in m.group(1).split(",")]
        l.sort()
        return "{%s}" % (", ".join(l),)

    replacement = re.sub(r'{(.*?)}', sub, data)
    with open("out.txt", "w") as out_file:
        out_file.write(replacement)

我用过re.sub()以便替换为已排序的就地匹配项。