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python turtle 速

转载 作者:太空宇宙 更新时间:2023-11-04 08:49:10 25 4
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我和我的 friend 正在使用 turtle 开发 Python 游戏。我们的问题在定义 turtle 的部分。我们正在尝试加快每只 turtle 的速度,但当我们这样做时,默认速度运行。为什么会出现这个问题?

import turtle


turtle.setup(1000,1000)
wn=turtle.Screen()
wn.title("Snake Game!")

#defines first turtle

t1=turtle.Turtle()
t1.pensize(2)
t1.speed(3)
t1.penup()
t1.goto(0,100)
t1.color("blue", "blue")
t1.pendown()

#defines second turtle

t2=turtle.Turtle()
t2.pensize(2)
t2.speed(3)
t2.penup()
t2.goto(0,-100)
t2.color("red", "red")
t2.pendown()

#defines outline

ol=turtle.Turtle()
ol.pensize(2)
ol.speed(7)
ol.penup()
ol.goto(450,0)
ol.color("black", "black")
ol.pendown()

ol.left(90)
ol.forward(300)
ol.left(90)
ol.forward(900)
ol.left(90)
ol.forward(600)
ol.left(90)
ol.forward(900)
ol.left(90)
ol.forward(300)
ol.hideturtle()

#defines score

score1=int(2)
score2=int(2)

def motion():
global move, score1, score2
move = True
path1 = []
path2 = []

#prints score


print("Player 1's score is", str(score1)+"!")
print("Player 2's score is", str(score2)+"!")

#defines motion

while move == True:
global pos1x, pos2x

t1.forward(1)
t2.forward(1)

pos1x = int(t1.xcor())
pos1y = int(t1.ycor())
t1xy = (pos1x, pos1y)

pos2x=int(t2.xcor())
pos2y=int(t2.ycor())
t2xy=(pos2x,pos2y)


path1.append(t1xy)
path2.append(t2xy)

#calculates score1

if t1xy in path2:
score1=int(score1-1)
print("")
print("Player 1's score is", str(score1)+"!")
print("Player 2's score is", str(score2)+"!")
t1.clear()
path1 = []
t2.clear()
path2 = []
t1.penup()
t1.goto(0,100)
t1.pendown()
t2.penup()
t2.goto(0,-100)
t2.pendown()
move = False



if score1==0:
print("Player 2 wins!")
exit()
else:
move==True



#calculates score2


if t2xy in path1:
score2=int(score2-1)
print("")
print("Player 1's score is", str(score1)+"!")
print("Player 2's score is", str(score2)+"!")
t2.clear()
path2 = []
t1.clear()
path1 = []
t2.penup()
t2.goto(0,-100)
t2.pendown()
t1.penup()
t1.goto(0,100)
t1.pendown()
move = False

if score2==0:
print("Player 1 wins!")
exit()
else:
move==True


#borders

if pos1x > 450:
t1.left(135)

if pos2x > 450:
t2.left(135)


if pos1x < -450:
t1.left(135)

if pos2x < -450:
t2.left(135)


if pos1y > 300:
t1.left(135)

if pos2y > 300:
t2.left(135)

if pos1y < -300:
t1.left(135)

if pos2y < -300:
t2.left(135)

#defines controls

def left():
t1.speed(500)
t1.left(45)
t1.speed(3)

def right():
t1.speed(500)
t1.right(45)
t1.speed(3)

def backwards():
t1.left(180)

def stop():
global move
move = False
t1.forward(0)
t2.forward(0)


def left2():
t2.speed(500)
t2.left(45)
t2.speed(3)

def right2():
t2.speed(500)
t2.right(45)
t2.speed(3)

def backwards2():
t2.left(180)

def motion2():

move = True
path1 = []
path2 = []


#onkeys

wn.onkey(left2, "Left")
wn.onkey(right2, "Right")
wn.onkey(backwards2, "Down")

wn.onkey(left, "a")
wn.onkey(right, "d")
wn.onkey(backwards, "s")

wn.onkey(motion, "t")
wn.onkey(stop, "y")
wn.onkey(motion2, "p")



wn.listen()
wn.mainloop()

最佳答案

你想在这里发生什么?

def left():
t1.speed(500)
t1.left(45)
t1.speed(3)

将速度设置为 10(快)以上会将其设置为 0(最快)。一旦操作完成,您就将其设置为 3(慢)。

据我所知,你暂时加快了 turtle 的速度,但它们并没有从中得到太多好处,例如left() 但是让 turtle 保持的速度进行应该从中受益的操作,例如运动()

我建议您取消所有的 speed() 调用并重新考虑它们,最好使用字符串参数“slowest”、“slow”、“normal”、“fast”和“fastest” "以帮助记录您正在做的事情并避免超出范围。

关于 python turtle 速,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37191039/

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