python - 使用值作为断点来分解列表？

Question

我有一个列表，其中包含一些值，每个值后跟一些 Nones:

['Apple', None, None, None, None, None, None, 'Orange', None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, 'Pear', None, None, None, None, None, None, None, 'Banana', None, None]

我想要这样的输出，它将列表分成单独的列表，每个列表都以非 None 值作为断点:

['Apple', None, None, None, None, None, None] 
['Orange', None, None, None, None, None, None, None, None, None, None, None, None, None, None, None, None] 
['Pear', None, None, None, None, None, None, None]
['Banana', None, None]

我正在为如何去做而绞尽脑汁。

Answer 1

你说你想用最新的非 None 值替换 None。我将跳过“如何拆分”问题，并回答“替换”问题:

def fill_nones(seq):
    last = None
    for val in seq:
        if val is not None:
            last = val
        yield last

现在您可以创建一个新列表:

filled = list(fill_nones(old_list))