c - 指针数组的不同声明

Question

假设我有一个指针数组:

char *names[] = { "Za" , "John"};

我可以这样声明吗:(?)

char **names = { "Za" , "John" }    

我尝试这样做的原因是我试图递增数组以打印其内容，以便我可以这样做:

printf("%s \n" , *(++names))

所以我可以让 printf 打印“John”。

我尝试了声明 char **names 并在编译时收到以下警告:

test.c: In function ‘main’:
test.c:6:2: warning: initialization from incompatible pointer type [enabled by default]
  char **names = { "Za" , "John"};
  ^
test.c:6:2: warning: (near initialization for ‘names’) [enabled by default]
test.c:6:2: warning: excess elements in scalar initializer [enabled by default]
test.c:6:2: warning: (near initialization for ‘names’) [enabled by default]

P.S 我的 C 文件名是 test.c

谢谢。

Answer 1

只需执行 char **pCurrentName = names;，然后您就可以执行 printf("%s\n", *(++pCurrentName)).