c - 既不是参数也不是指针

Question

数组的新手，我不断收到错误消息，即在 selectLocation 函数中下标值既不是指针也不是 vector 。这只是井字游戏程序的开始。我做错了什么？

void selectLocation(char board[],int choice);
void displayBoard(char[]);
#include <stdio.h>

int main()
{
    char board[3][3];
    int i;

    for (i=0;i<8;i++)
    {
        displayBoard(board);
        selectLocation(board,i);
    }

return 0;
}

void displayBoard(char board[])
{
    printf("    0   1   2");
    printf("\n   --- --- --- ");
    printf("\n0 |   |   |   |");
    printf("\n   --- --- --- ");
    printf("\n1 |   |   |   |");
    printf("\n   --- --- --- ");
    printf("\n2 |   |   |   |");
    printf("\n   --- --- --- ");
}

void selectLocation(char board[],int choice)
{
    int x,y;

    printf("Enter a location for X or O in x,x format");
    printf("\nex. '0,1' '1,2'");
    scanf("%d,%d",&x,&y);

    if (choice%2==1)
    {
        board[x][y]='X';
    }
    else
    {
        board[x][y]='O';
    }
}

Answer 1

board[x][y]='X';

board 不是 2D 数组，你会得到那个错误。

board[x]

仅有效。因为您收到的是 char 数组而不是 2D 数组。
所以在定义和声明中更改函数的签名以接收二维数组，

void selectLocation(char board[][3],int choice)
{
    int x,y;
    ...

和

void displayBoard(char board[][3])
{