java - 如何在 JAVA 中的 diff 原因上打印相同 NumberFormatException 的 diff 消息？

Question

如何在 JAVA 中的 diff 原因上打印相同 NumberFormatException 的 diff 消息？

try {
 int a=Integer.parseInt(aStr);
int b= Integer.parseInt(bStr);
}catch (NumberFormatException ex) { 
 if ex's cause is from int a;//ex.getCause()=a?
System.out.println("a is not a integer"); 
 if ex's cause is from int b
System.out.println("b is not a integer");
}

Answer 1

      try {
         final int a = Integer.parseInt(aStr);
      } catch (final NumberFormatException ex) {
         System.out.println("a is not a integer");
      }
      try {
         final int b = Integer.parseInt(bStr);
      } catch (final Exception e) {
         System.out.println("b is not a integer");
      }