python - 将一个列表的内容循环弹出到列表列表中

Question

我有一个 list

main_list = [1,2,3,4,5,6,7,8,9,10,11,12]

我想将列表分成多个列表，我想要如下所示的输出-

list1 = [1,9]    
list2 = [2,10]    
list3 = [3,11]    
list4 = [4,12]    
list5 = [5]    
list6 = [6]    
list7 = [7]
list8 = [8]

Answer 1

这可以使用 itertools.cycle 在几行中解决。

from itertools import cycle

main_list = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12]
lists = [[] for _ in range(8)]

for x, y in zip(cycle(lists), main_list):
     x.append(y)

复杂度:O(n)。

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print(lists)
[[1, 9], [2, 10], [3, 11], [4, 12], [5], [6], [7], [8]]