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c - Switch-Case 语句似乎卡住了我的循环

转载 作者:太空宇宙 更新时间:2023-11-04 08:38:25 26 4
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这是我正在处理的程序中的几个循环。程序似乎在 printf("TEST2"); 之后停止前进。一切一目了然。有什么我想念的吗?

我希望循环在设置 switch 语句中的值后重复。我知道它至少通过了一次。

#include "stdafx.h"
#include <stdlib.h>
#include <time.h>

char *names[] = { "Denise", "Inja", "Jane", "Karen", "Maggie", "Margaret", "MJ", "Queen", "Sherri", NULL }; //ptr for names, 9 nurses
const char days[5][10] = { "Monday", "Tuesday", "Wednesday", "Thursday", "Friday" };
int randomNurse();
#define total_nurses 9 //number of nurses on staff
#define days_in_week 5 //number of work days in a week


int main() {

srand(time(NULL));
int day, pos, candidate, i, j;
int slackers[4] = { 1, 1, 1, 1 }; //array that holds the selections for who isn't working
char **name_ptr = names;
/*0 = Denise, 1 = Inja, 2 = Jane, 3 = Karen, 4 = Maggie, 5 = Margaret, 6 = MJ, 7 = Queen, 8 = Sherri*/
int avail_nurses[total_nurses] = { 1, 1, 1, 1, 1, 1, 1, 1, 1 }; //holds the status of each nurse, 0 = unavailable, 1 = available

/*prints names */
int temp_counter = 1; //counter
while (*name_ptr) {
printf("%i) %s\n", temp_counter, *name_ptr);
name_ptr++;
temp_counter++;
}

/*this assumes that no more than FOUR nurses will be away on any given week*/
printf("\nEnter numbers that correspond to the nurses who won't be available for the week.\nType up to four numbers, each separated by a space.\n");
printf("When you are done, press \"Enter\".\n");
printf("If less than four nurses will be on leave, type a \"0\" in place of a selection.\n");
printf("Example: 1 2 5 0\n\n\n");

/*week selection of unavailable nurses*/
do {
printf("Who won't be here? ");
} while (scanf("%i %i %i %i", &slackers[0], &slackers[1], &slackers[2], &slackers[3]) != 4);

/*checks the selections made, and sets the available nurses to the correct value, zero if they are slacking||vacationing*/
for (int n = 0; n < 4; n++) {
int slacker = slackers[n];
if (slacker >= 1 && slacker <= 9)
avail_nurses[slacker] = -1;
}


/*-----WEEKLY_ASSIGNMENT-----*/
int pos_per_day[days_in_week] = { 5, 9, 9, 8, 5 }; //number of nurses needed each day

int selection[days_in_week][total_nurses]; //the selected nurses per day

for (i = 0; i < days_in_week; i++) {
for (j = 0; j < total_nurses; j++) {
selection[i][j] = -1; //initialize to -1 which means no nurse is selected
}
}

//fill all the days of week
for (day = 0; day < days_in_week; day++) {
for (pos = 0; pos < pos_per_day[day]; pos++) { //for every position needed that day
do {
candidate = randomNurse();
} while (!avail_nurses[candidate]); //looks for available nurses (phrasing)

avail_nurses[candidate] = 0; //change nurses status to not available
selection[day][pos] = candidate; //fill the output array with appropriate nurse
}
for (i = 0; i < total_nurses; i++) {
avail_nurses[i] = 1; //initialize the nurses status for next day use
}
for (int n = 0; n < 4; n++) { //make sure we shame the slackers...
int slacker = slackers[n];
if (slacker >= 1 && slacker <= 9)
avail_nurses[slacker] = -1;
}
}

/*-----PRINTS SCHEDULE FOR WEEK-----*/
for (i = 0; i < days_in_week; i++) {
printf("%-10s: ", days[i]);
for (j = 0; j < total_nurses; j++) {
if (selection[i][j] != -1)
printf("%-10s ", names[selection[i][j]]);
}
printf("\n");
}
return 0;
}

/*function to generate random nurse*/
int randomNurse() {

return rand() % 9; //random number 0-8, to pick nurse
}

最佳答案

您有未定义的行为。 pos_per_day 中的第二个值是 9,它超出了 select 数组的范围。从该数组中的每个值中减去一个可能足以修复它。

其他不良问题:

  • 您需要在scanf 之后验证输入数据。
  • switch 语句完全没有必要。将其替换为计算。
  • 不要对变量使用大写。按照惯例,这仅适用于已定义的常量。
  • 不要像 5 和 9 这样的硬编码数字。用定义的常量替换它们。

必须学习如何使用可用的调试器调试像这样的简单程序。

关于c - Switch-Case 语句似乎卡住了我的循环,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/25089614/

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