python - 查表并在python中拆分句子

Question

我有一个列表如下。

mylist = ['test copy', 'test project', 'test', 'project']

我想看看我的句子是否包括前面提到的 mylist元素并从第一个匹配中拆分句子并获得其第一部分。

例如:

mystring1 = 'it was a nice test project and I enjoyed it a lot'

输出应该是:it was a nice

mystring2 = 'the example test was difficult'

输出应该是:the example

我目前的代码如下。

for sentence in L:
    if mylist in sentence:
        splits = sentence.split(mylist)
        sentence= splits[0]

但是，我收到一条错误消息 TypeError: 'in <string>' requires string as left operand, not list .有办法解决这个问题吗？

Answer 1

您需要另一个 for 循环来遍历 mylist 中的每个字符串。

mylist = ['test copy', 'test project', 'test', 'project']
mystring1 = 'it was a nice test project and I enjoyed it a lot'
mystring2 = 'the example test was difficult'

L = [mystring1, mystring2]
for sentence in L:
    for word in mylist:
        if word in sentence:
            splits = sentence.split(word)
            sentence= splits[0]
            print(sentence)
# it was a nice 
# the example