c - 字符串的子串并打印出来

Question

我想剖析以下字符串:

char msg[30] ="Hello 13 1";
char *psh;
int num1;
int num2;
char s[30],s[30];

我试试这个但是:

pch = strtok (msg," ");
while (pch != NULL)
  {
    printf ("%s\n",pch);
    pch = strtok (NULL, " ");
   }

哪些输出:

 Hello
 13
 1

我只想让数字“13”等于 num1，数字“1”等于 num2:

    printf("%d\n",num1);

    Output: 13


    printf("%d\n",num2);

    Output: 1

我尝试:

 sscanf(sc, "%s %d %d", &s, &num1, &num2);

哪些输出:

 Segmentation fault

谢谢

[编辑]

 char * pch
 char s[30];
char sc[30];
char num1[30];
char num2[30];



 pch = strtok (s," ");
 while (pch != NULL)
 {
   printf ("%s\n",pch);
   pch = strtok (NULL, " ");
 } 

 sscanf(sc, "%s %d %d", pch, &num1, &num2);

Answer 1

使用 sscanf功能:

sscanf(msg, "%s %d %d", s, &num1, &num2);

这会导致您的代码看起来像这样:

#include <stdio.h>
int main()
{
    char msg[30] = "Hello 13 1";
    int num1, num2;
    char s[30];
    sscanf(msg, "%s %d %d", s, &num1, &num2);
    printf("%d\n%d\n", num1, num2);
    return 0;
}